5. A dominant mutation in mice (T) causes loss of tails, while a recessive allele (t) allows for normal tail development. A gene on another chromosome can result in Straight tails (S) but the recessive allele (s) results in the curly tails. True or False: If a Tt; Ss mouse has offspring with a tt Ss mouse, the chance of an offspring having a straight tail is 3/4.

5. A dominant mutation in mice (T) causes loss of tails, while a recessive allele (t) allows for normal tail development. A gene on another chromosome can result in Straight tails (S) but the recessive allele (s) results in the curly tails. True or False: If a Tt; Ss mouse has offspring with a tt Ss mouse, the chance of an offspring having a straight tail is 3/4.

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Description: Genetics Question 5 5. A dominant mutation in mice (T) causes loss of tails, while a recessive allele (t) allowsfor normal tail development. A gene on another chromosome can result in Straight tails(S) but the recessive allele (s) results in the curl

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
2. Uniparental disomy is a rare phenomenon in whichonly one of the parents of a child with a recessivedisorder is a carrier for that trait; the other parent ishomozygous normal. By analyzing DNA polymorphisms, it is clear that the child received both mutantalleles from the carrier parent but did not receive anycopy of the gene from the other parent.a. Diagram at least two ways in which uniparentaldisomy could arise. (Hint: These mechanismsall require more than one error in cell division,explaining why uniparental disomy is so rare.)Is there any way to distinguish between thesemechanisms to explain any particular case ofuniparental disomy?
2. Uniparental disomy is a rare phenomenon in whichonly one of the parents of a child with a recessivedisorder is a carrier for that trait; the other parent ishomozygous normal. By analyzing DNA polymorphisms, it is clear that the child received both mutantalleles from the carrier parent but did not receive anycopy of the gene from the other parent.a. Diagram at least two ways in which uniparentaldisomy could arise. (Hint: These mechanismsall require more than one error in cell division,explaining why uniparental disomy is so rare.)Is there any way to distinguish between thesemechanisms to explain any particular case ofuniparental disomy?b. How might the phenomenon of uniparental disomyexplain rare cases in which girls are affected withrare X-linked recessive disorders but have unaffectedfathers, or other cases in which an X-linked recessive disorder is transmitted from father to son?c. If you were a human geneticist and believed oneof your patients had a disease syndrome caused…
1. Hair or fur length in cats is controlled by a single, autosomal gene; the short hair-allele is dominant to the allele for long hair. Hair color is produced by a different gene which is located on the X chromosome. One allele for this sex-linked gene produces yellow, while an alternate allele produces black fur color; individualswhich are heterozygous for these alleles are calico or tortiseshell in color.If a long-haired, black male is mated with a calico female homozygous for short hair what kind of kittens will be produced in the Ej generation? Give both genotypes and phenotypes; express the genotypes bothsymbolically and in words. Label answers clearly!!
9. Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___
. In mice, the dominant allele Gs of the X-linked geneGreasy produces shiny fur, while the recessive wildtype Gs+ allele determines normal fur. The dominantallele Bhd of the X-linked Broadhead gene causesskeletal abnormalities including broad heads andsnouts, while the recessive wild-type Bhd+ alleleyields normal skeletons. Female mice heterozygousfor the two alleles of both genes were mated withwild-type males. Among 100 male progeny of thiscross, 49 had shiny fur, 48 had skeletal abnormalities,2 had shiny fur and skeletal abnormalities, and 1 waswild type.a. Diagram the cross described and calculate thedistance between the two genes.b. What would have been the results if you hadcounted 100 female progeny of the cross?
6. A person is simultaneously heterozygous for two autosomal genetic traits. One is a recessive condition foralbinism (alleles A and a); this albinism gene is foundnear the centromere on the long arm of an acrocentricautosome. The other trait is the dominantly inheritedHuntington disease (alleles HD and HD+). TheHuntington gene is located near the telomere of oneof the arms of a metacentric autosome. Draw all copies of the two relevant chromosomes in this person asthey would appear during metaphase of (a) mitosis,(b) meiosis I, and (c) meiosis II. In each figure, labelthe location on every chromatid of the alleles forthese two genes, assuming that no recombinationtakes place.
0. In Drosophila, the gene for cinnabar eye color is onchromosome 2, and the gene for scarlet eye color is onchromosome 3. A fly homozygous for both recessivecinnabar and scarlet alleles (cn/cn; st/st) is white-eyed.a. If male flies (containing chromosomes with thenormal gene order) heterozygous for cn and st allelesare crossed to white-eyed females homozygous forthe cn and st alleles, what are the expected phenotypes and their frequencies in the progeny?b. One unusual male heterozygous for cn and st alleles,when crossed to a white-eyed female, produced onlywild-type and white-eyed progeny. Explain the likelychromosomal constitution of this male.c. When the wild-type F1 females from the cross withthe unusual male were backcrossed to normal cn/cn;st/st males, the following results were obtained:wild type 45%cinnabar 5%scarlet 5%white 45%Diagram a genetic event at metaphase I that couldproduce the rare cinnabar or scarlet flies among theprogeny of the wild-type F1 females.
6) In fruit flies, red eyes are dominant (E). White eyes are recessive (e). If the female fly has white eyes and the male fly has homozygous dominant red eyes, what are the possible phenotypes and genotypes of their offspring? Genotypes: EE: Phenotypes: Red Eyes: Ee: White Eyes: е:
5 f There are two genes that determine the coat colour expression in dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype MM Mm mm Phenotype White AAY Half colour (Grey or light red) Full colour (Black or Red) 1. If a dog breeder wants to determine the unknown genotype of a dog, what colour of dog must she use as a testcross? 2. A white dog was testcrossed, and all of the puppies had light red coats. What is the genotype of the white dog? Use a Punnett square to show your work. Hint - When a trait is controlled by two genes, an individual's genotype consists of 4 letters. = = = B I 123 ||| 14 E E I ос C GO * ●● ● ●0 00 00 00 ✓ C U up X₂ x²
15. Albinism in corn plants is caused by a recessive lethal gene that results in death before maturity. What will the adult phenotypic ratio be for the F1 generation of heterozygous parents? 16. Huntington's chorea is a dominant lethal in humans. The disease does not appear until later in life, so that afflicted individuals may already have produced children. What are the F1 genotypic and phenotypic ratios of parents who are homozygous dominant and heterozygous?
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?