41. A homozygous tall and blue individual with a short homozygous purple individual. Draw your chart below. a. What are the two parents genotypes: b. What are their children's genotypes: с. What are their children's phenotypes: d. What is their phenotypic ratio: e. What percent of each phenotype are their children:

41. A homozygous tall and blue individual with a short homozygous purple individual. Draw your chart below. a. What are the two parents genotypes: b. What are their children's genotypes: с. What are their children's phenotypes: d. What is their phenotypic ratio: e. What percent of each phenotype are their children:

Name: 41.A homozygous tall and blue individual with a short homozygous purp
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Description: 41.A homozygous tall and blue individual with a short homozygous purple individual. Draw yourchart below.a.What are the two parents genotypes:b.What are their children's genotypes:C.What are their children's phenotypes:d.What is their phenotypic rat

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 5RQ: Imagine that you are performing a cross involving seed texture in garden pea plants. You cross...

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[Type here] 8. Using the letter "A", write the genotype(s) for a homozygous trait. a. Write the genotype(s) for a heterozygous trait. 9. Using the letter "B", write the genotype(s) for a dominant trait. a. Write the genotype(s) for a recessive trait. Complete the Punnett Square using the information provided. Grey fur is dominant to white fur. Red eyes are dominant to black eyes. F = Grey Fur f = White Fur E = Red eyes 10. The bunny is heterozygous for gray fur. Write her genotype. braM e = Bla
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1 . 3 Below are the results of some blood tests and you need to compare the child's blood type to the parent's blood type and confirm paternity. If there is no way that parents with the indicated blood types could give rise to a child with the child's blood type write 'No'. If it is possible write 'Yes' and include the parent's genotypes. Child Mom and Dad Possible? If Yes Ogenotypes AB and B O. A and B AB and A АВ A and O A and B 2.
The chart below is showing 4 generations of a family that is affected by a hereditary disease. a. Is the disorder being tracked dominant or recessive? How do you know? b. There is only one possible genotype for person C. True or False? c. What are the possible genotypes for person A? d. What are the possible genotypes for person B?, e. If two people with the same genotypes as person C's spouse and person A's spouse had a child, what is the probability that the child will be affected by this genetic disorder? (draw a Punnett square using the correct genotypes to help you). % chance offspring will be affected % chance offspring will not be affected
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What are the possible genotype and phenotype of offspring witha parent of two heterozygous tall pea plant? Legend: T- tall pea plant t- short pea plant1. Identify the genotypes of the parents 2. Complete the punnett square 3. What are the possible genotypes of the offspring. 4. What is the genotypic ration 5. What are the possible phenotypes of the offspring 6. what is the phenotypic ratio 7. What is the probability of having short trait.
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a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…
A cross between a bird with blue feathers and a bird with white feathers produces offspring with silver feathers. The color of the birds is determined by only two alleles. Show a punnet square. 1 What are the genotypes of the parent birds? 2 What is the genotype of the bird with silver feathers? 3 Can you figure out the phenotypic ratios of the offspring of two birds with silver feathers?