4 Transition to turbulent boundary layer 3 Cylinder (two-dimensional) 1 Sphere 10 102 103 104 105 106 107 Reg = PUd (a)
4 Transition to turbulent boundary layer 3 Cylinder (two-dimensional) 1 Sphere 10 102 103 104 105 106 107 Reg = PUd (a)
Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)
8th Edition
ISBN:9781305387102
Author:Kreith, Frank; Manglik, Raj M.
Publisher:Kreith, Frank; Manglik, Raj M.
Chapter8: Natural Convection
Section: Chapter Questions
Problem 8.36P
Related questions
Question
The sphere is dropped in gasoline at 20 ° C.
Ignoring its acceleration phase, what will it's terminal (constant)
fall velocity be, from Fig. ?
![4
Transition to turbulent
boundary layer
3
Cylinder (two-dimensional)
1
Sphere
10
102
103
104
105
106
107
Reg =
PUd
(a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcf8014cb-b5ef-427e-99fb-1f5591340862%2Fd49754cf-1fd2-46b2-89f6-091c346987f9%2F2yq4e3.png&w=3840&q=75)
Transcribed Image Text:4
Transition to turbulent
boundary layer
3
Cylinder (two-dimensional)
1
Sphere
10
102
103
104
105
106
107
Reg =
PUd
(a)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
For gasoline at 20°C, take ρ ≈ 680 kg/m3 and μ ≈ 2.92E−4 kg/ms. For steel take ρ ≈ 7800 kg/m3. Then, in “terminal” velocity, the net weight equals the drag force:
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