3. The force of interest 8(t) at time t (measured in years) is a + bt² where a and b are constants. An amount of £200 at time t = 0 accumulates to £210 at t = 5 and £230 at t = 10. (a) Show that 1 a = log (1.05) log(1.15) = 0.008352, and b = - 250 log(1.15) 15 log(1.05) = 0.0001687. (b) Compute A(0, 7) and hence compute the discounted value at t = 0 of a payment of £750 due at t = 7. (c) Compute A(6, 7). What is the equivalent constant annual interest rate for the year from t = 6 to t = 7? (d) Calculate the constant force of interest that would give rise to the same accumulation from t = 0 to t = 10.

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
Question
3. The force of interest 8(t) at time t (measured in years) is a + bt² where a and
b are constants. An amount of £200 at time t = 0 accumulates to £210 at t = 5
and £230 at t = 10.
(a) Show that
1
a = log (1.05) log(1.15) = 0.008352,
and
b
=
-
250 log(1.15) 15 log(1.05) = 0.0001687.
(b) Compute A(0, 7) and hence compute the discounted value at t = 0 of a
payment of £750 due at t = 7.
(c) Compute A(6, 7). What is the equivalent constant annual interest rate for
the year from t = 6 to t = 7?
(d) Calculate the constant force of interest that would give rise to the same
accumulation from t = 0 to t = 10.
Transcribed Image Text:3. The force of interest 8(t) at time t (measured in years) is a + bt² where a and b are constants. An amount of £200 at time t = 0 accumulates to £210 at t = 5 and £230 at t = 10. (a) Show that 1 a = log (1.05) log(1.15) = 0.008352, and b = - 250 log(1.15) 15 log(1.05) = 0.0001687. (b) Compute A(0, 7) and hence compute the discounted value at t = 0 of a payment of £750 due at t = 7. (c) Compute A(6, 7). What is the equivalent constant annual interest rate for the year from t = 6 to t = 7? (d) Calculate the constant force of interest that would give rise to the same accumulation from t = 0 to t = 10.
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