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3. Solve: bivor Minimize 2x₁ + 2x25x3 3x1 + 2x2 + 4x3 = 7 subject to x1-x2+3x3 = 2 750 10/11 X1, X2, X3 ≥ 0. ibus vabi aniv

3. Solve: bivor Minimize 2x₁ + 2x25x3 3x1 + 2x2 + 4x3 = 7 subject to x1-x2+3x3 = 2 750 10/11 X1, X2, X3 ≥ 0. ibus vabi aniv

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.9: Dividing Real Numbers
Problem 11MRE
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3. Solve: Dobivor Minimize 2x₁ + 2x2 — 5x3 offrw subject to 3x1 + 2x2 + 4x3 = 7 and to elet x1 - x2 + 3x3 = 2 1850 Of burebird 1, 2, 3 ≥ 0. (10 552 (28 bao1T ZOITOUNTE 985 s vlasplo otisw 920 hinja sil
Transcribed Image Text:3. Solve: Dobivor Minimize 2x₁ + 2x2 — 5x3 offrw subject to 3x1 + 2x2 + 4x3 = 7 and to elet x1 - x2 + 3x3 = 2 1850 Of burebird 1, 2, 3 ≥ 0. (10 552 (28 bao1T ZOITOUNTE 985 s vlasplo otisw 920 hinja sil
#3 Cont + R₂ 10 Q R₁-5R2 R3+10R₂ 5R₂ R₁ +422 R3 + 2 R₂ 1217 (2 + ² R₁ min -10X₁ - 6x2 +8x3 St. bv jX₂ X45 510 X 4 XI 1-10 5 1 Pela |--10 1 blo O 5 X ₁-2 X2 +6X3 + xy = 110 X₁ + 4x₂ - 6x3 + x5 X₁1 X21 X 31 X4 X5 20 X41 X1 5/2 0 X4 10 X25/2 5 X4 10/3 X2 5/2 5 X3 10/3 X215 25/3 X₂ -2 니 -6 -2 NOWYJNIN 5 1-4 D to -2 - X3 X4 X5 6 O 0 1 O 1 O 4 -2 0 1 0 9/20 9 1 80 OOOOOOO 0 -3 1 20 91 2 3. 1 - 23/20 1-1 1 30 to 3 30 5 -3/1/20 -bo-o 01/12 32 1 -2/22 = 20 =30 1 21/12 1 ib 20 30 O 20 3 O i/c 5 15/2 3/2 45 1/3 16 35/3 1/4 15/2 30 35) O 3/2/45 43 16 35/3 25 ½/22 5/3 170/3
Transcribed Image Text:#3 Cont + R₂ 10 Q R₁-5R2 R3+10R₂ 5R₂ R₁ +422 R3 + 2 R₂ 1217 (2 + ² R₁ min -10X₁ - 6x2 +8x3 St. bv jX₂ X45 510 X 4 XI 1-10 5 1 Pela |--10 1 blo O 5 X ₁-2 X2 +6X3 + xy = 110 X₁ + 4x₂ - 6x3 + x5 X₁1 X21 X 31 X4 X5 20 X41 X1 5/2 0 X4 10 X25/2 5 X4 10/3 X2 5/2 5 X3 10/3 X215 25/3 X₂ -2 니 -6 -2 NOWYJNIN 5 1-4 D to -2 - X3 X4 X5 6 O 0 1 O 1 O 4 -2 0 1 0 9/20 9 1 80 OOOOOOO 0 -3 1 20 91 2 3. 1 - 23/20 1-1 1 30 to 3 30 5 -3/1/20 -bo-o 01/12 32 1 -2/22 = 20 =30 1 21/12 1 ib 20 30 O 20 3 O i/c 5 15/2 3/2 45 1/3 16 35/3 1/4 15/2 30 35) O 3/2/45 43 16 35/3 25 ½/22 5/3 170/3
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