3. A 6.50 kg block is pressed against a vertical wall by a force (F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.40 and the directional angle 8 for the force is 36.0°. Determine the magnitude of the force (F) when the block is about to slide down the wall. N ssfox s 50 ssf60 ssf60 ssf60 ssf6 6 sf60 ss sf60 ssf60 ssf60 ssf60 ssf60 s $ 09Jss (Diss 09JSS ssf ssf60 ssf60 ssf6 ssf60 ssf60 ssf60 ssf60 ssf60 ssf60 ssf60 ssf60

Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter6: Applications Of Newton’s Laws Of Motion
Section: Chapter Questions
Problem 11PQ: In Problem 10, the mass of the sign is 25.4 kg, and the mass of the potted plant is 66.7 kg. a....
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3. A 6.50 kg block is pressed against a vertical wall by a force (F), as shown in the figure below. The coefficient of static
friction between the block and the wall is 0.40 and the directional angle 0 for the force is 36.0°. Determine the magnitude
of the force (F) when the block is about to slide down the wall.
N
60 ssf60 ssf60 ssf60 ssfor
une (9Jss (9jss (9jss
F
0
ssf60 ss
SI
160 ssfox ssf60 ssf60 ss160 ssf60
ssf60 ssf ster
f60 ssf60 ssf60 ssf60 ssf60 ssf60
◊ ssf60 ssf60 ssf60
Transcribed Image Text:3. A 6.50 kg block is pressed against a vertical wall by a force (F), as shown in the figure below. The coefficient of static friction between the block and the wall is 0.40 and the directional angle 0 for the force is 36.0°. Determine the magnitude of the force (F) when the block is about to slide down the wall. N 60 ssf60 ssf60 ssf60 ssfor une (9Jss (9jss (9jss F 0 ssf60 ss SI 160 ssfox ssf60 ssf60 ss160 ssf60 ssf60 ssf ster f60 ssf60 ssf60 ssf60 ssf60 ssf60 ◊ ssf60 ssf60 ssf60
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