3, 10, 5, 20, 30, 88, 45, 57, 89 20, 10, 5, 30, 3, 89, 4.5, 57, 88 88, 10, 5, 30, 3, 89, 45, 57, 20 30, 10, 5, 20, 3, 88, 45, 57, 89 3, 10, 5, 30, 20, 89, 45, 57, 88

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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5

3, 10, 5, 20, 30, 88, 45, 57, 89
20, 10, 5, 30, 3, 89, 4.5, 57, 88
88, 10, 5, 30, 3, 89, 45, 57, 20
30, 10, 5, 20, 3, 88, 45, 57, 89
3, 10, 5, 30, 20, 89, 45, 57, 88
Next Page
Transcribed Image Text:3, 10, 5, 20, 30, 88, 45, 57, 89 20, 10, 5, 30, 3, 89, 4.5, 57, 88 88, 10, 5, 30, 3, 89, 45, 57, 20 30, 10, 5, 20, 3, 88, 45, 57, 89 3, 10, 5, 30, 20, 89, 45, 57, 88 Next Page
A = [30, 10, 5, 89, 57, 88, 45, 3, 20]
Given pivot item 30, and partition() function below, A will be after first call.
int partition(int a[], int lo, int hi) {
int i = lo, j = hi+1;
while (true){
while (small(a[++i], a[lo]}}
if (i
hi) break;
while (small(a[lo], a[--j]))
= lo) break;
if (j
if (i >= j) break;
swap(a, i, j):
}
swap(a, lo. j);
return j;
Transcribed Image Text:A = [30, 10, 5, 89, 57, 88, 45, 3, 20] Given pivot item 30, and partition() function below, A will be after first call. int partition(int a[], int lo, int hi) { int i = lo, j = hi+1; while (true){ while (small(a[++i], a[lo]}} if (i hi) break; while (small(a[lo], a[--j])) = lo) break; if (j if (i >= j) break; swap(a, i, j): } swap(a, lo. j); return j;
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