2,d'y(0) = -2 dt? d'y(t) , dy(t) dy0) - + 3 dt = sec(t), y(0) = 2, dt %3D %3D dt

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 36CR
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You can solve the given initial value problem by changing the parameter method.

d’y(1) , dy(t)
+
dt
= sec(t), y(0) = 2,
dt
dy0) -
2,dy(0)
= -2
%3D
%3D
dt
dt?
2
Transcribed Image Text:d’y(1) , dy(t) + dt = sec(t), y(0) = 2, dt dy0) - 2,dy(0) = -2 %3D %3D dt dt? 2
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