29- In a turning operation on brass with hardness 125 HB, the cutting speed = 200 m/min, teed = 0.25 mm/rev, and depth of cut -7.5 mm. How much power will the lathe draw in performing this operation if its mechanical efficiency 90%. Use the table given below to obtain the appropriate specific energy value. Specific Energy U or Unit Power Pu Brinell Unit Horsepower HP, hp/(in '/min) Material Hardness N-m/mm in-lb/in Carbon steel 150-200 1.6 240,000 0.6 201-250 2.2 320,000 0.8 251-300 2.8 400,000 1.0 Alloy steels 200-250 2.2 320,000 0.8 251-300 2.8 400,000 1.0 301-350 3.6 520,000 1.3 351-400 4.4 640,000 1.6 Cast irons 125-175 1.1 160,000 0.4 175-250 1.6 240,000 400,000 0.6 Stainless steel 150-250 2.8 1.0 Aluminum 50-100 0.7 100,000 0.25 Aluminum alloys 100-150 0.8 120,000 0.3 Brass 100-150 2.2 320.000 0.8 Bronze 100-150 2.2 320,000 0.8 Magnesium alloys 50-100 0.4 60,000 0.15 a) 21,007 b) 38.194 C) 10.503 d) 16,667

29- In a turning operation on brass with hardness 125 HB, the cutting speed = 200 m/min, teed = 0.25 mm/rev, and depth of cut -7.5 mm. How much power will the lathe draw in performing this operation if its mechanical efficiency 90%. Use the table given below to obtain the appropriate specific energy value. Specific Energy U or Unit Power Pu Brinell Unit Horsepower HP, hp/(in '/min) Material Hardness N-m/mm in-lb/in Carbon steel 150-200 1.6 240,000 0.6 201-250 2.2 320,000 0.8 251-300 2.8 400,000 1.0 Alloy steels 200-250 2.2 320,000 0.8 251-300 2.8 400,000 1.0 301-350 3.6 520,000 1.3 351-400 4.4 640,000 1.6 Cast irons 125-175 1.1 160,000 0.4 175-250 1.6 240,000 400,000 0.6 Stainless steel 150-250 2.8 1.0 Aluminum 50-100 0.7 100,000 0.25 Aluminum alloys 100-150 0.8 120,000 0.3 Brass 100-150 2.2 320.000 0.8 Bronze 100-150 2.2 320,000 0.8 Magnesium alloys 50-100 0.4 60,000 0.15 a) 21,007 b) 38.194 C) 10.503 d) 16,667

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q1. The part shown below will be turned in two machining steps. In the first step a length of (50 + 50) = 100 mm will be reduced from Ø100 mm to Ø80 mm and in the second step a length of 50 mm will be reduced from Ø80 mm to Ø60 mm. Calculate the required total machining time T with the following cutting conditions: Cutting speed V=80 m/min, Feed is f=0.8 mm/rev, Depth of cut 3 mm per pass. Ø100 Ø80 Ø60 50 50
Q24. For the below figure please write its part program. The depth of the cut is 0.25 inches (Finishing operation), while the tool's diameter is 0.5 inches. Consider the speed and feed. -0.75- - - 1.0 60⁰ RO.25 (0, 0) 0.75-
A 5 m wide by 12 m long and 20 mm thick steel plate is to be cut into 8 equal parts lengthwise. If the cutting rate is 3.75 mm per stroke using a hacksaw with a speed of 200 rpm, how long will it take the job in hours. There is only one cut stroke per revolution. D O 1.78 O7.18 O 1.87
A cylindrical mild steel work piece of Ø55 X 200mm undergoes a turning operation on a lathe machine to reduce the diameter to Ø 45mm. The cutting parameters are 23 m/minute, 0.3 mm/ revolution and 0.5 mm are cutting speed, feed and depth of cut respectively. Determine the following. i) Time for single pass (minutes). ii) Find number of passes required to reduce the diameter from Ø55 to Ø45mm. iii) Total time required to complete the turning operation in minutes (Tfinal).
Find the machining time to complete the job as shown below from the basic raw material of 50 mm diameter and 100 mm length. Assume the following data: cutting speed for turning and boring = 25 m/min, feed for turning and boring = 0.5 mm/rev, cutting speed for drilling = 20 m/min, feed for drilling = 0.25 mm/rev, depth of cut not to exceed = 5 mm? 40 25 20 20 20 20
What is the cutting speed of turning in the unit of m/min, when main axis spindle speed is 2,409 rpm and external diameter is 86mm ? Answer in 2 decimal points. Calculate the theoretical spindle rotational speed in rpm required to drill a 1 mm hole in copper using high speed steel drill. The recommende cutting speed is as following. The thickness of the copper plate is 24. (Leave the answer in numerical value, no need to key in 'rpm') Typical cutting speeds (m/min) High speed steel Material Tungsten carbide Aluminum 100 500 60 330 Copper Hard brass 45 230 Bronze 35 180 Mild steel 28 250 Cast iron 20 160
1. If a machinist wanted to drill a % inch hole in a piece of machine steel using a high speed steel drill. At what speed in revolutions per minute should he operate the drill press? 2. Find the revolutions per minute of an 8 mm drill if it is used to cut an aluminum workpiece using a high carbon steel drill. 3. The rpm setting of the drill press is set to 600 rpm. What is the maximum diameter in inches of a high speed drill if it is used to drill a tool steel material? 4. A drill press has the following rpm settings; 350, 600, 1100, & 1600. What rpm setting must be used if a 15 mm high speed steel drill is used to cut brass workpiece? 5. A machine operator drills a hole of a 3/8 inch diameter to a stainless steel using a carbon steel drill. He sets the drill press rpm setting to 900 rpm. Is he operating at correct setting? If not, then what must be the correct rpm setting considering that the machine has the following rpm settings of 300, 600, 900, 1200, and 1800?
A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutes
A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutes (a) Find number of passes to finish the entire turning operation ( (b) The actual length of the turning operation in mm ('
A mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 49 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.2 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 4mm (iii) Total time required to complete the turning operation is 52.6 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpm
Please solve it correctly , Don't Use Ai tool. (1) A twist drill bit is used to drill a hole of diameter 2.0 at 4578.1 rpm at a feed rate of 2.5 in/min. Calculate the MRR in in^3/min. Take "pi" = 3.14. Round your answer to the nearest tenth.
A mild steel specimen of Initial diameter of 32.5 mm is turned to final diameter of 25 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.3 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 6 mm, over run length is 3mm (iii) Time required to complete one single turning operation is 2.3 minutes (a)Find number of passes to finish the entire turning operation (b) Total time required to complete the turning operation in minutes (c) Spindle speed in in rpm (d) Cutting speed in m/minutes