Analytical Chemistry part 2 25.00 mL of 0.041 32 M Hg₂(NO3)2 were titrated with 0.057 89 M KIO3.Hg₂+ + 2103 → → Hg₂(103)2(S)lodateFor Hg2 (103)2, Kp = 1.3 X 10-¹8. Find [Hg2+] in the solution after addition of (a) 34.00 mLof KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point.Find [Hg₂²+] at 34.50 and 36.5 mL. Compute as well the pHg for all the points.

As per bartleby guidelines i have to solve only first question

25.00 mL of 0.041 32 M Hg₂(NO3)2 were titrated with 0.057 89 M KIO3. Hg2+ + 2103 → Hg2(103)2(s) lodate For Hg₂ (103)2, Kp = 1.3 X 10-¹8. Find [Hg3*] in the solution after addition of (a) 34.00 mL of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point.

25.00 mL of 0.041 32 M Hg₂(NO3)2 were titrated with 0.057 89 M KIO3. Hg2+ + 2103 → Hg2(103)2(s) lodate For Hg₂ (103)2, Kp = 1.3 X 10-¹8. Find [Hg3*] in the solution after addition of (a) 34.00 mL of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point.

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter22: An Introduction To Electroanalytical Chemistry

Section: Chapter Questions

Problem 22.10QAP

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Question

Analytical Chemistry part 2

25.00 mL of 0.041 32 M Hg₂(NO3)2 were titrated with 0.057 89 M KIO3.
Hg₂+ + 2103 → → Hg₂(103)2(S)
lodate
For Hg2 (103)2, Kp = 1.3 X 10-¹8. Find [Hg2+] in the solution after addition of (a) 34.00 mL
of KIO3; (b) 36.00 mL of KIO3; and (c) at the equivalence point.
Find [Hg₂²+] at 34.50 and 36.5 mL. Compute as well the pHg for all the points.

Branch of chemistry that deals with the separation, identification, and quantification of chemical compounds. Instruments such as centrifuges, microscopes, and spectrometers are commonly used in analytical chemistry. Forensic science is well-known for being reliant on analytical chemistry techniques.

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