23. Tertiary butyl chloride undergoes substitution by hydroxide ion according to the equation below. (CH3)3CCI- + OH → (CH3)3COH + Cl Experimental evidence showed that the reaction obeys the rate law, Rate = k [(CH3)3CCI]. Which of the following mechanisms is consistent with the observed rate law? Step 1 -(CH3)3CCI+ OH → (CH3)3C + HOCI Slow a. Step 2-(CH3)3C + HOCI (CH3)3COH + CI Fast b. Step 1 -(CH3)3CCI→ (CH3)3C + Cl Slow Step 2 -(CH3)3C + OH (CH3)3COH Fast c. (CH3)3CCI + OH → (CH3)3COH + Cl d. Step 1 -(CH3)3CCI → (CH3)3C + Cl Fast Step 2-OH → H+0² Slow e. Step 3 -(CH3)3C+0²+H(CH3)3COH Fast Step 1 -(CH3)3CCI + OH (CH3)3C + HOCI Fast Step 2 -(CH3)3C + HOCI → (CH3)3COH + CI Slow

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100%
ill have
C.
would be m
luble in an
2.16 g/mc
issolved i
1x10-3
nia has a
.63
aturated s
he solubil
0.17.
ressure of
went
holes of v
p. 43.0
d in oil c
g of dipl
.14 °C 1
.00 °C/1
b. 27
23. Tertiary butyl chloride undergoes substitution by hydroxide ion according to the equation below.
(CH3)3CCI + OH → (CH3)3COH + CI
Experimental evidence showed that the reaction obeys the rate law, Rate = k [(CH3)3CCI]. Which of the following
mechanisms is consistent with the observed rate law?
Step 1-(CH3)3CCI + OH → (CH3)3C + HOCI Slow
Step 2 -(CH3)3C + HOCI
b. Step 1 -(CH3)3CCI (CH3)3C + Ch Slow
(CH3)3COH + Cl Fast
Step 2 -(CH3)3C + OH (CH3)3COH Fast
c. (CH3)3CCI + OH → (CH3)3COH + Cl
d. Step 1 -(CH3)3CCI→ (CH3)3C + Cl Fast
Step 2 - OH → H+0² Slow
Step 3 -(CH3)3C+0²+H(CH3)3COH Fast
e.
Step 1 -(CH3)3CCI + OH
(CH3)3C + HOCI Fast
Step 2 -(CH3)3C + HOCI→ (CH3)3COH + Cl Slow
Transcribed Image Text:ill have C. would be m luble in an 2.16 g/mc issolved i 1x10-3 nia has a .63 aturated s he solubil 0.17. ressure of went holes of v p. 43.0 d in oil c g of dipl .14 °C 1 .00 °C/1 b. 27 23. Tertiary butyl chloride undergoes substitution by hydroxide ion according to the equation below. (CH3)3CCI + OH → (CH3)3COH + CI Experimental evidence showed that the reaction obeys the rate law, Rate = k [(CH3)3CCI]. Which of the following mechanisms is consistent with the observed rate law? Step 1-(CH3)3CCI + OH → (CH3)3C + HOCI Slow Step 2 -(CH3)3C + HOCI b. Step 1 -(CH3)3CCI (CH3)3C + Ch Slow (CH3)3COH + Cl Fast Step 2 -(CH3)3C + OH (CH3)3COH Fast c. (CH3)3CCI + OH → (CH3)3COH + Cl d. Step 1 -(CH3)3CCI→ (CH3)3C + Cl Fast Step 2 - OH → H+0² Slow Step 3 -(CH3)3C+0²+H(CH3)3COH Fast e. Step 1 -(CH3)3CCI + OH (CH3)3C + HOCI Fast Step 2 -(CH3)3C + HOCI→ (CH3)3COH + Cl Slow
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