200N 500N 600 N.m 3 m 4m 2m 45 2 m + 150 N 400N 5m

Q: 0.8 1 0.8 m 0.8 m D 0.6 m E 1.2 m 1.2 m y F 1.2 m

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Q: 600 N 800 N m B 1.5 m 1.5 m 2 m 2 m 45 D Fig. C

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Q: 20 KN/m 10 KN/m 學 2.00 1.70 1.30

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Q: 400 N/m В 3 m 3 m

A: Let RA and RB are the reactions at A and B By using law of equilibrium  ΣFy =0 RA+RB = (1/2)X400X6…

Q: 6 m 3m 4 m 4 m 4 m 6 m 3 m m 4 m

A: Write coordinates of A,B,C and DA=0,0,3.5B=3,4,4C=-6,-3,6D=4,-3,4

Q: 20 KN 10 KN 10KN/m 15KN/m 10 KN/m B. 1.00 1.00 2.00 1.00

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Q: 4 m/s 6 m/s? A 30 0.6 m 30°

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Q: 600 N 400 N 800N 24 m 78 m

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Q: Fig. 2 F = 300 N = 250 N 309 60° 2 m 3 m 4 m B F= 500 N Fig. 3

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Q: 1000 N/m В A C |D 0.2 m 0.2 m 0.25 m

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Q: 5 m A 30 kN B 5 m 5 m 5 m 5 m 20 KN 5 m 5 m E

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Q: 35 N 1.5 m 3m B 30 N 2m 45° 40 20 N

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Q: 70 m/s 60 m A 30 km/h В 2.5 m 350 m

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Q: 1.0 m 2.6 m 2.6 m 1600 N/m 900 N/m

A: Prismatic cantilever beam EI=1200 KN-m2 Taking section at a distance x from the free end. By similar…

Q: 166 kN HOKM 2 bokN 4m 4m 2m 4mi 3m 3m

A: In step 1 we draw given diagram and calculate reaction forces:-

Q: 50KN 20 kN 1OKN/M 3m 1m 2 m Figure 1

A: Given

Q: 2. The density of water in FPS. a. 62.297 lbs/cubic ft. b. 60 lbs/cubic ft. c. 60.85 lbs/cubic ft.…

A: GIVEN DATA- A question given about density of Water We have to select correct option

Q: 2 kN 2 kN 2 kN/m 3 kN/m B 3.5 m 15 m 2 m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: 500 N/m 1.5 b В + x m 2 m 2 m

A: to find : Reaction Force at B (RB) =?

Q: W=4 kN/m 5 kN A 2.5 m + 1.5 m

A:

Q: 1000 N 90 2000 N 90 1000 N 90 90 90° 130° 30 GG 12 m 12 m 12 m 1000 N

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Q: Im 35 N/m 2m 30 N Im в 85 N 100 N.m 60 2m 2m 0.5m 1.5 m

A: Mechanical Equilibrium: A body is said to be in mechanical equilibrium if it satisfies the following…

Q: 500 N 300 N 45 2.5 m

A: The given system of force is shown below,

Q: 2 m. 2 m. B cable 0=60° w =30 kN bar B

A: Concept Of Mechanics Used.

Q: 6 m G m- m- 40KN 40KN 40KN

A:

Q: | 3.00 cm 100. kPa 1.50 m .00 cm 4.00 m/s

A: For solution refer below images.

Q: X2 (t) X1(t) 2N f(t) m M1 M2 4kg 3kg 2 N.s 3 N.s 1Ns оо m m

A:

Q: 2 tór/m 8 ton F 4 ton-m E 3 ton/m 2 m 4 m Im1m 2 m 2 m

A: According to the principal of engineering mechanics  Reaction and moment at support is equal to zero

Q: 96 30 lb/ft 180 Ib · ft - 9 ft - 4.5 ft M (lb · ft) 200

A:

Q: C cord 2m 1.5m 10 N B. 56 N.m 2.5m E- 0.25m F 3m 1.5m 3m

A: Find the reactions at point B on member ABC

Q: |4 m 3 m 3 m A 3 m 3 m G 3 m 3 m

A: Calculating reaction at support, RA+RB=30+30+90RA+RB=150 kN   .......... (1)Taking moment about…

Q: س)1( : اذا كانت منظومة القوى المبينة بالشكل )1( هي منظومة متزنة ، احسب القوة T والزاوية 0 60 20 lb…

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Q: Water 0,9 m R = 0,75 m 0,75 m K Water F 1,5 m 2m

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Q: NAVN 20 m P=4 kN 1.5 m

A: Moment is maximum when the force vector is perpendicular to the line of joining between the point of…

Q: 650 N 350 N 125 N/m 12m 18m 2m 2m 2m

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Q: |20 kN 15 kN/m A 2 m 4 m B.

A: The reactions on the supports of beam can be drawn as follows,

Q: 60 21.65ft 30 2000lbf 50ft 50ft

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Q: A 0.8 ft 4.8 ft 60 lb 3.5 ft E 48 lb 1.8 ft B |C D 3.6 ft

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Q: 500 N-m/m A 1000 N-m/m 0.5 m. 0.5 m B

A: Given that the shaft is A-992 steel.  The diameter of the shaft is 60 mm, Draw the free-body diagram…

Q: 1cm t1 (cm) →P 3,2 cm t2 (cm) t1 (cm) 1 cm 中中 20 çm b (cm) P. →P P = 20t Dp=1,6 cm

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Q: 30cm зост 30 сm 30 сm 100 сm 20сm 50 cm 30 ст

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Q: 2 n 1.5 m C A 2 m 2 m 3 m

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Q: 3 m 6 m A 400 N C 300 N x' 2 m B

A: For solution refer below images.

Q: 600 N 300 300 F E 120 N-m 60° 60 G 200 400 200

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Q: 2.5 kN 1.5 kN 3 kN 30 A B. 2m 4m 2m

A: Resolve the two forces along the beam and perpendicular to the beam as shown. Write the x component…

Q: 15 ft 150 Ib 35 5ft 2 ft 250 Ib 25

A: