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20. Calculate AG, and the equilibrium constant at 25°C for the reaction below for a reaction mixture of 1.0 atm of N₂(g), 3.0 atm of H₂(g), and 0.50 atm of NH3(g). N2(g) + 3 H2(g) = 2 NH3(g) AG=AG+RTlnQ Find AG from standard energy of formations, then find AG using the above expression.

20. Calculate AG, and the equilibrium constant at 25°C for the reaction below for a reaction mixture of 1.0 atm of N₂(g), 3.0 atm of H₂(g), and 0.50 atm of NH3(g). N2(g) + 3 H2(g) = 2 NH3(g) AG=AG+RTlnQ Find AG from standard energy of formations, then find AG using the above expression.

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.20QE: The equilibrium constant for a reaction decreases as temperature increases. Explain how this...
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20. Calculate AG, and the equilibrium constant at 25°C for the reaction below for a reaction mixture of 1.0 atm of N2(g), 3.0 atm of H₂(g), and 0.50 atm of NH3(g). N2(g) + 3 H2(g) = 2 NH3(g) AG=AG +RTlnQ Find AG from standard energy of formations, then find AG using the above expression. AG = -32.821kj AG = 44.4 kj AG=-RTInK Solve for K K= 5.66X 105 page 6 of 8
Transcribed Image Text:20. Calculate AG, and the equilibrium constant at 25°C for the reaction below for a reaction mixture of 1.0 atm of N2(g), 3.0 atm of H₂(g), and 0.50 atm of NH3(g). N2(g) + 3 H2(g) = 2 NH3(g) AG=AG +RTlnQ Find AG from standard energy of formations, then find AG using the above expression. AG = -32.821kj AG = 44.4 kj AG=-RTInK Solve for K K= 5.66X 105 page 6 of 8
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