2.Explain how each type of impurity can be removed from the desired compound during recrystallization: soluble, insoluble and colored impurities
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2.Explain how each type of impurity can be removed from the desired compound during recrystallization: soluble, insoluble and colored impurities
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- 1. Explain how distillation works in separating simple mixtures. 2. Differentiate simple distillation and fractional distillation. 3. What is an effective way of preventing irregular ebullition or bumping of the mixture during distillation?This method of purification is applied when the purity has a lower vapor pressure than the purified sublimation O recrystallization distillation O extractionb) Will the sample be contaminated with any of the impurities? Calculate the percent purity of the initial sample (in terms of compound A) - ( i.e. express the amount of compound A in the initial sample as a percentage of the mass of initial sample). Calculate the percent purity of the final sample (in terms of compound A) - (i.e. express the amount of compound A in the final sample as a percentage of the mass of final sample). Did the recrystallization procedure result in an increase of the percent purity of compound A in the sample? Comment on the results.
- What does the process of recrystallization accomplish? 1) Place toxic chemicals into pure materials 2) Lower potency of pharmaceutical raw materials 3) Purify organic compounds U 4) Remove impurities from crude materialsA chemist wishes to mix a solution that is12% acid. She has on hand 8 liters of a 8% acid solution and wishes to add some16% acid solution to obtain the desired 12% acid solution. How much 16% acid solution should she add? A chemist wishes to mix a solution that is 12% acid. She has on hand 6 liters of a 4% acid solution and wishes to add some 16% acid solution to obtain the desired 12% acid solution. How much 16% acid solution should she add?Describe the solubility property of animal oil and plant oil in different solvents and solutions.Can you please tell me if its soluble, slightly or insoluble and why.Test tube #1: distilled water + animal oil = Test tube #2: distilled water + plant oil =Test tube #3: acetone + animal oil =Test tube #4: acetone + plant oil =Test tube #5: ethanol + animal oil =Test tube #6: ethanol + plant oil =Test tube #7: diluted HCl + animal oil =Test tube #8: diluted HCl + plant oil =
- A group was given the responsibility of performing a recrystallization experiment in their laboratory to see if the three newly found solvents could purify and separate a mixture including compounds A and B. The following are the solubilities of the two compounds in g/100 mL of hot and cold solvents: Solubility in g/100 mL solvent A B Solvent Hot Cold Hot Cold 1 4.60 1.10 5.30 1.90 2 6.40 5.80 8.40 1.10 3 9.70 3.30 6.80 1.70 What is the %recovery and %purity of A and B in the chosen solvent? Show solutions pls4. Calcium Hydroxide Solution (Lime Water) and olive oil are used because an emulsifying agent is formed in situ when these 2 solutions are agitated together. What is the emulsifying agent that is formed? a. calcium succinate b. calcium oleate c. succinic hydroxide d. palmitic hydroxide2 Compound A has a room-temperature solubility of 30.2 g/L in a certain solvent, while compound B has a solubility of 9.5 g/L in the same solvent at room temperature. An extract from a plant contains 110 g of A and 8 g of B. How much A can in principle be crystallized in pure form from this mixture if 3 L of solvent is used? How much solvent is required to dissolve the amount of B contained in this mixture? Show your steps.
- What are the names of these structures? Which ones are soluble in water?Where should heat be applied to a test tube? Bottom of the test tube. Top of the test tube. Middle of the test tube. The point at which the solution is highest in the tube. Anywhere is fine.It was determined that benzoic acid (structure below) is not soluble in water. However, it can be reacted with certain substances to promote its solubility in water. One of these substances is: ОН 6 M HCI O 6 M NaHCO3 6 M acetic acid (CH3CO2H) O 6 M NaCl
