2. The tank shown contains alcohol (SG=0.78) and covered by a circular plug 1.2 m in diameter. Calculate the hydrostatic force F 6m acting on the plug and its center of pressure. 40
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A: absolute reading of the guage = patm = po+P mercury = 50 KPa + 13.6 *9.81*0.5 = 116.7 KPa
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- The hemispherical glass bowl is filled with water. Find the location y of the center of gravity of the filled bowl. Approximate the bowl as a thin shell of radius R=6.15in. Use 1=162lb/ft3 for glass and 2=62.4lb/ft3 for water.Calculate the resultant force caused by the water acting on the parabolic arch dam. The water levels are 16 ft on the upstream side and zero on the downstream side. For water, use =62.4lb/ft3.Determine the volume of the concrete arch dam.
- In the Fig. is shown the cross-section of the tank full of water under pressure. The length of the tank is 2.5 m. An empty cylinder lies along the length of the tank on one of its corners as shown. Find the horizontal and vertical components of the force acting on the curved surface LMN of the cylinderQ3/Determine the height water will rise due to capillary action in a clean 0.25 in. diameter tube. What will be the height if the diameter is reduced to 0.01 in. Consider o= 5.03*10-3 lb/ft and y= 62.4 lb/ft³.A B с OIL WATER 1.0M 0.5m In the tank open to the atm. shown in the figure below, there is on oil layer 1 meter high on a 0.5 meter high water layer. Since pont & is in the Middle of paints A and C. calculate the pressures at points A, B, C, D in Kla. (Density of water 1000 kg/m³, density of oil 800 kg/m³)
- what is the total hydrostatic force acting on the tainter sector gate? (in lbs)ii. If the surface tension of the drop be 42.27x103 N/m, find the pressure difference of the dropNote: Please state what formula you are using. And please be clear and detailed with your solution. Atleast explain. It will help me, thanks. Problem: A Triangular gate having a horizontal base of 1.30 m and an altitude of 2 m is inclined 45o from the vertical with vertex pointing upward. The base of the gate is 2.70 m below the surface of oil (s = 0.80). What normal force must be applied at the vertex of the gate to open it? Show figure
- A large open container contains at the top, and water at the bottom. The height of the vessel is 3.66 m. The water level is 0.61 m measured from the bottom. The remaining portion is filled with the oil having a density of 917kg/m^3. A. Calculate the pressure in Pa at a distance of 3.05 m from the top. B. Calculate the total pressure in Pa at the bottom of the tank3_Calculate the volume if it is v1=1.5 L, P1= 100 Кра, р2- 50 kpa.2. Calculate the resultant force on the submerged rectangular window in the vat below due to the fluid pressure. Indicate its direction and locate the center of pressure on the diagram (Vweter = 9810 N/m'). %3D 2 m 1.5 m 2 m t0.75 m 1.75 m Oil (s.g. = 0.80) 45