2. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond) → C(graphite) using the following information. NOTE: Not all of the formulas are needed. C(diamond) → C(graphite) AHan = ? 1. C(diamond) + Oz(g) → CO2(g) 2. 2 CO2(g) → 2CO(g) + O2(g) 3. C(graphite) + Oz(g) → CO2(g) 4. 2 CO(g) → C(graphite) + CO2(g) AH = -395.3 kJ AH = 566.0 kJ AH = -393.5 kJ AH = -172.5 kJ

Chemistry: Principles and Practice
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Chapter5: Thermochemistry
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Question 2 from The Additivity of Heats (Hess's Law) Worksheet asks you to determine the change in enthalpy for the conversion of C(diamond) into C(graphite).  Based on these results how much heat (kJ) would be required to convert 1.00 grams of graphite into diamond?  Do not type units into your answer.

2. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes
to graphite so slowly the enthalpy change of the process must be obtained indirectly. Determine
AHxn for C(diamond) → C(graphite) using the following information. NOTE: Not all of the formulas
are needed.
C(diamond) → C(graphite) AHan= ?
1. C(diamond) + Oz(g) → CO2(g)
2. 2 CO2(g) → 2CO(g) + O2(g)
3. C(graphite) + O{g) → CO2(g)
4. 2 CO(g) → C(graphite) + CO2(g)
AH = -395.3 kJ
AH = 566.0 kJ
AH = -393.5 kJ
AH = -172.5 kJ
Transcribed Image Text:2. Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly the enthalpy change of the process must be obtained indirectly. Determine AHxn for C(diamond) → C(graphite) using the following information. NOTE: Not all of the formulas are needed. C(diamond) → C(graphite) AHan= ? 1. C(diamond) + Oz(g) → CO2(g) 2. 2 CO2(g) → 2CO(g) + O2(g) 3. C(graphite) + O{g) → CO2(g) 4. 2 CO(g) → C(graphite) + CO2(g) AH = -395.3 kJ AH = 566.0 kJ AH = -393.5 kJ AH = -172.5 kJ
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