2.) Dam; Given: Density of conc.=2350kg/cu m, Uplift pres. is max. at d heel to zero at d toe, Req'd: a) FSo, b) FSs if coef. of fric.= 0.86 c) max. soil pres. at the base. 13.8m 3m Gm
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- Qi/ A 5m deep deposit of silty sand lies above a 4m deep deposit of gravel. The gravel is under- lain by a deep layer of stiff clay. The ground water table is found 2m below the ground surlace. The Soil properties are :- of sand below GWT = 1.75 Mg/m³ Isat of gravel 2.05 Mg/m ³ Isat of sand above G.WT = 1.7 Mg/m²³ 2 Draw The distribution of vertical total stress, Pore water pressure, and vertical effective stress with depth down to the clay layer. P = 1.7 My/m²³- $t1 = 1.95 Mg/m³, silty sand Seat - 2.05 Mg/m²/ G.L G.WT I gravel still clay) 4mhere are the answer, only need solutions 1.f = 11.46 MPa 2.Mcr= 88.90 kN-m 3.fconc= 17.14 MPa; fsteel= 318.20 MPaPROBLEM 1: A BOREHOLE ATA SITE REVEAL THE SOIL PROFILE SHOWN IN FI6URE. DETERMINE THE TDIAL AND EFFECTIVE STRESSES AT ELEVATION 2D 00m 2.0m 3.0m VERY FINE SAND W= 5%., S: 40 /. FINE SAND W : 12., S-80/. FINE SAND W : 121. 5.4m SDFT CLA Y, W- 28 FDR ALL SDIL USE GS 2.7 20. Lom
- QA 5m deep deposit of silty sand lies above a 4m deep deposit of The Uneler- gravel. gravel is lain by a deep layer of stiff clay. The ground water table is found 2m. below the ground sur lace. The Soil Properties are:- of Bal Sand below GWT = 1.75 Mg 1 m³ Pat Isat of gravel = 2.05 Mg/m³ sat of sand above G.WT = 1.7 Mg/m³ Draw The distribution of vertical total stress, Pore water pressure, and vertical effective stress with depth down to the clay layer. 0 = 8xh 8 = 1.7 Mg/m³ Sat St But = 1.95 Mg/m³ = 2.05 Mg/m³ D GWT silty sand G.L gravel clay H 5⁰ma) Find ming a gene ar failu with a factor of safety of 3. Then, b) What will be the allowable load if the water table rises to the ground surface level. c) G.S. Ys= 17 kN/m³ O = 32° C=13 kPa Dry soil %3D 1.25 m 1.5 1.0 m x 1.0 m W.T. Ysat.= 18 kN/m³ (þ = 30° Saturated soil C=12 kPaCalculate 6,µand 6' with depth. H1 = 6 ft, H2 = 4 ft. H3= 9.0 feet Degree of Saturation in capillary rise zone ,S= 50% Dry sand Gs = 2.68, e=0.543 Clay Gs = 2.735 , e = 0.765 Bottom clay Gs = 2.752, e= 0.967 H3 Dry sand Clay; zone of capillary rise Clay Rock ーミ
- Q1 along points A,B,C,D 5m A 5m Soil A 5m Soil B 2m 3m 3m Datum I kA = 10 kgQ-1: Estimate the consolidation settlement due to the lowering of the water table from the location No. 1 to the location No. 2 in the soil profile. 1 6 m Sand 2 Ya(sand) =17kN/m3 2 m Ysat(sand) = 19kN /m³ 4 m Clay LL = 40%, e, =0.95 Y sat(clay) =18.6kN/m³ BedrockThe embankment for a highway 5097 ft long, 104 ft wide and 6 ft in compacted thickness is to be constructed from a sandy soil trucked from a borrow pit. The water content of the sandy soil in the borrow pit is 6.748% and its porosity is 0.422. The specification requires the embankment be compacted to a dry unit weight of 122.874 lb/ft3. The specific gravity is 2.588. Determine the following: a. Total weight of the soil solids, kips. b. Total volume of the soil required from the borrow pit, ft3. c. Weight of water to be added per foot length of the embankment to reach 10% moisture content, lb.Round off answers to three decimal places.
- The embankment for a highway 5097 ft long, 104 ft wide and 6 ft in compacted thickness is to be constructed from a sandy soil trucked from a borrow pit. The water content of the sandy soil in the borrow pit is 6.748% and its porosity is 0.422. The specification requires the embankment be compacted to a dry unit weight of 122.874 lb/ft3. The specific gravity is 2.588. Determine the following: a. Total weight of the soil solids, kips. b. Total volume of the soil required from the borrow pit, ft3. c. Weight of water to be added per foot length of the embankment to reach 10% moisture content, lb.A normally consolidated clay that have c-20 and Ø = 30 if 0.5P - 0.3q=23 find: 1-0₁f and σ3f 2-0nf and of inonShear Strentgh of the soil 2012