2. (a). Two steel plates are joined by bolts. Details are given below. Determine the load factor NL, factor of safety against separation nseparation for constant axial load of 18000 N per bolt. Bolts are threaded completely. Diameter of the bolt dbolt = 16 mm, tensile stess area of bolt At = 157 mm², Sp = 600 MPa, Sut= 600 MPa, Syt = 600 MPa, thickness of members are 20 mm each, E = 207 GPa. (b). If the external load per bolt is varying between 0 to 18000 N, determine fatigue factor of safety, nr, and the factorof-safety against yielding, nyield. Fatigue endurance limit is Se = 129 MPa.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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2. (a). Two steel plates are joined by bolts. Details are given below. Determine the load factor
nL, factor of safety against separation nseparation for constant axial load of 18000 N per bolt.
Bolts are threaded completely.
Diameter of the bolt dbolt = 16 mm, tensile stess area of bolt At = 157 mm², Sp = 600 MPa,
Sut 600 MPa, Syt = 600 MPa, thickness of members are 20 mm each, E = 207 GPa.
(b). If the external load per bolt is varying between 0 to 18000 N, determine fatigue factor of
safety, nr, and the factorof-safety against yielding, nyield.
Fatigue endurance limit is Se = 129 MPa.
Transcribed Image Text:2. (a). Two steel plates are joined by bolts. Details are given below. Determine the load factor nL, factor of safety against separation nseparation for constant axial load of 18000 N per bolt. Bolts are threaded completely. Diameter of the bolt dbolt = 16 mm, tensile stess area of bolt At = 157 mm², Sp = 600 MPa, Sut 600 MPa, Syt = 600 MPa, thickness of members are 20 mm each, E = 207 GPa. (b). If the external load per bolt is varying between 0 to 18000 N, determine fatigue factor of safety, nr, and the factorof-safety against yielding, nyield. Fatigue endurance limit is Se = 129 MPa.
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