2. A sample of pure sodium chloride (MW = EW = 58.44 ) weighing 0.2286 g is dissolved in water and exactly 50.00 mL of silver nitrate solution is added to precipitate AgCl. The excess Ag* is titrated with 12.56 mL of a 0.0986 N solution of KSCN. Calculate the normality of the AGNO3 solution.

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A: The answer is 2.47g. Here in this question  1. First you have to find out moles of AgCl so that you…

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Q: A 0.5123g sample (molar mass 204.23g/mol) of KHP was dissolved in about 25 mL of distilled water and…

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A: Volume of the standard solution = 40 ml or 0.04 L Let the concentration (M) of the standard solution…

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A: a) from the molarity eqution , M1V1 = M2V2 , we have M1 x 84.3 ml = 2 x 64.6ml x  0.0948  M M1 =…

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A: The volume of the given solution is 21.70 mL which is equal to 0.0217 L. The number of moles of…

Q: 0.250 g sample of impure CaCl2 is titrated with 40.00 mL  0.105 M AgNO3 solution. Calculate the…

A: Given: 1) Mass of impure CaCl2 = 0.25 g 2) Volume of AgNO3 = 40 mL 3) Concentration of AgNO3 = 0.105…

Q: Calculate the solubility (in g/L) of Aluminum sulfide (Al2S3) In 0.25 M Al+3 solution. (standard…

A:

Q: Titration of 0.2342 g of pure Na,C,O, (134.0 g/mol) required 33.45 ml of KMNO, solution according to…

A: Given :-  Mass of Na2C2O4 = 0.2342 g  Molar mass of Na2C2O4 = 134.0 g/mol  Volume of KMnO4 solution…

Q: A 1.00 g sample of an iron ore is dissolved in acid and then reduced to Fe²⁺. It was then titrated…

A: The titration involves: 5Fe2+ +MnO4−+8H+→5Fe3++Mn2++4H2O

Q: A 40.0 mL volume of 1.80 M Fe(NO3)3 is mixed with 21.5 mL of 0.808M Fe(NO3)3 solution. Calculate the…

A: Given that, volume of Fe(NO3)3 solution V1= 40.0 mL = 0.04 L, molar concentration M1= 1.80 M Another…

Q: 35.00 mL of a solution of KIO3 reacted with exactly 35.00 mL of a 0.1000 M solution of KI in acid…

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A: Chemical equation: Na2SO4  +   BaCl2   ------>   BaSO4  +  2NaCl Number of moles of BaSO4 =…

Q: A solution was prepared by dissolving 367 mg of K3Fe(CN)6 (329.2 g/mol) in sufficient water to give…

A:

Q: Titration of 0.2342 g of pure Na,C,0, (134.0 g/mol) required 33.45 ml of KMNO, solution according to…

A: Given :- mass of Na2C2O4 = 0.2342 g   Molar mass of Na2C2O4 = 134.0 g/mol   Volume of KMnO4 solution…

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Q: platinum in this solution as well as b) the molar concentration of the platinum in this solution.…

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Q: A 40-mL vial of a sodium chloride was diluted to a liter with sterile water. The concentration (w/v)…

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Q: When 38.0 mL of 0.1250 M H,SO, is added to 100. mL of a solution of PbI,, a precipitate of PbSO,…

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Q: A sample of freshly precipitated and filtered silver chloride weighs 459.0 mg. If 1.00 % of the…

A: The chemical equation representing the decomposition reaction of silver chloride is shown below.

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Q: a) In the gravimetric analysis the precipitate should be free from impurities. Give the detailed…

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A: Given information: Mass of sample = 1.5 g Mass of precipitate = 0.65 g

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Q: 2.23 gr sample taken from a bleaching powder is dissolved and completed to 250 ml. Taken from here…

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Q: 1, What is the gravimetric factor for converting a weight of silver chloride, AgCl (MM=143.321…

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Q: A piece of an unknown weighing 12.50is placed in 49.7cm of water in a cylinder. The water level…

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Q: A 20 mL volume of 0.015 M KIO3 containing an excess of KI, is added to a 0.312 g sample of a Real…

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Q: lodide (atomic mass 126.9 g/mol) in water was determined by the Volhard method. A 20.00 mL aliquot…

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Q: compounds can be toxic and must be removed from wastewater. Aqueous mercury (II) nitrate is a toxic…

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Q: om the following data calculate the normalities of the acid and base solutions: weight of pure…

A: Here, Nax 0.982=  Nbx 1ml Acid as, 0.2448105.98 =Va ×Na2.31×10-3 =Va ×Na Then, 0.84Nb =43.65-VaNa