2) On the graph below, draw a potential energy diagram for the following reaction: Q + R → S + T given the following information: PE of Q + R= 150 kJ PE of S + T = 250 kJ PE of the activated complex = 375 kJ 400 E 350- 300 250 200 150 100 50 0- Reaction coordinate

2) On the graph below, draw a potential energy diagram for the following reaction: Q + R → S + T given the following information: PE of Q + R= 150 kJ PE of S + T = 250 kJ PE of the activated complex = 375 kJ 400 E 350- 300 250 200 150 100 50 0- Reaction coordinate

Chemistry for Today: General, Organic, and Biochemistry

9th Edition

ISBN:9781305960060

Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen

Publisher:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen

Chapter20: Enzymes

Section: Chapter Questions

Problem 20.2E: List two ways that enzyme catalysis of a reaction is superior to normal conditions.

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Question

Calculate the EA for the forward
reaction.

2) On the graph below, draw a potential
energy diagram for the following
reaction:
Q +R + S + T
given the following information:
PE of Q + R= 150 kJ
PE of S + T = 250 kJ
PE of the activated complex = 375 kJ
400
2 350-
300-
250
200
150
100
50
Reaction coordinate
Potential energy (kJ)

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