(2,-3) (8,-6)

Q: -2 -3 dimSpan-2 3 6.

A: See the detailed solution below.

Q: (3,५४)- (2 । ) (x-1 2. 3. 2.

A:

Q: т-2 5m-2 3 3

A: It is given that,m-23=5m-23 We have to find the value of m.

Q: (b) (-1)" (b)(-1)*+-

A:

Q: (-2, 0), (6, -3), (-4, 6), (-6, 4)

A:

Q: U-5/7=62/3

A: Solve the equation for U as follows.

Q: 2h-3>15

A: 2h-3>15  add 3 both sides 2h-3+3>15+3

Q: (-2, 5) (8,-3)

A: Explanation of the solution is given below...

Q: -1 2 4, 3 A = -1 2

A:

Q: 3 2 3 3-

A:

Q: (-7,0) and (-2,4) (5,9) and (-7,-7) (4,6) and (-4,-3) (-6,-10) and (-2,-10)

A: we know that, distance between two points(x1,y1) and (x2,y2) is, distance = ( (x2-x1)2 - (y2-y1)2…

Q: 4 (-2, -2) (0,-2) 55. (-1, -3)F 4.

A:

Q: -2 / -11 7.

A: We have to find the determinant of given matrix

Q: (-6,0) -7,-2)5

A: Solution - Vertex of the parabola are given as  - (-6, 0) We know the general equation of a…

Q: {(3.-1), (-1,0), (2, 6), (-3, -8)}

A:

Q: (-3,9) (-3,-5)

A: In (-3,9) and  (-3,-5) x ordinate = -3 for both.So on the line joining them x is fixed.

Q: (a®j3 (7а)? 2 (-3a*)³ 3 3

A: The explanation of answer as follows

Q: а. А- {(2, -3), (1, 0), (0, 0), (-1, -1)} b. B= {(a, b)|b = e*} с. С- (х, у) у - 2х + 1}

A: a. The given set is A=2,-3,1,0,0,0,-1,-1. Here, there are different x values and for each x value,…

Q: X1 3x, = -2 Зх, + х, — 2х, — 5 2х, + 2х, + х; —D 4 2x3 X3 =

A:

Q: -23+3k>-5

A: Given that  -23+3k>-5 To solve the above expression.

Q: (6, -4) and (-2, 6)

A: Given: - The points are, (6,-4) and (-2,6) To find: - The equation for the line that passes through…

Q: x#-3,0,3 6.

A: Here we want to simplify the given expression.

Q: -6 -3 -4 -5 A = 1 and B = 3 1 6

A:

Q: 3b-4=28-b b=?

A:

Q: 4 y = -x-8 8. (14,-16)

A: Given equation is y = (4/7)x - 8

Q: Question Image -5 2 3 4 5 -2 -3 -4 -5 %23

A: Answer

Q: 3. 3(22+7)-

A:

Q: -5,4y+14-2y=4

A: Given ,  4y + 14 - 2y = 4     ....... (1)  We have to find value of y  (1) implies

Q: (-1, -7), (-2, 0)

A:

Q: А. (-4, 2) В. (2, 4) О с. (2,4) D. (-2,-4)

A: The rules of reflection points are: If the point is reflected over the x-axis, the coordinate of y…

Q: -5+2(8-12)

A: Use PEMDAS rule to simplify.First we work with the parenthesis. In it 8-12=-4

Q: {(-5, 7), (-6, -8), (1, -2), (10, 3) }

A:

Q: (-1,-3), (9, 0) 9. (-4,-4), (-1,-1)

A: we knew that distance between two points (x1,x2) and (y1,y2) are  x1-y12+x2-y22. so 8. distance…

Q: 4-3 9M - 16

A: 7) Here we have,

Q: Simplify. (-9,²+ 7y+2) + (-5y² +6y+5)- (4,² – 3y+ 6)

A: (-9y2+7y+2)+(-5y2+6y+5)-(4y2-3y+6)

Q: passes through (3, -7) and (4, -11)

A: Given: Points (3,-7) and (4,-11)

Q: 3=-6+r

A:

Q: (-5,-1) and (6,-5)

A:

Q: -3.5 -2 and j = -2 1.5

A:

Q: d. (-1,4) 11π b. (-3,) c. (3,- 6 5π 2

A: (r, θ)=-3, 11π6(x, y)=(r cosθ, r sinθ)        =-3cos11π6, -3 sin11π6       =-332, 32In the second…

Q: A=-6 9. 2 4 3 -5

A:

Q: (5y-9)(7y-10)=0

A: Given expression is

Q: " - 3 +1 - x+7 .2 م الاكم ح أن

A: We are given 6x+1=3x+3 to find the values of 2x+7

Q: (-4,-6) A (-4, 6) B © (-6,4) D(-6,-4)

A: The coordinate of A is A(4,6)

Q: 1) y'-y = 3 3) у'+2у%3 бе"

A: We will solve the differential equation,  using the form dy/dx + Py = Q

Q: -5+a=6a

A: Solve the following equation

Q: 4) Tro

A: answer is in next step

Q: [ 2, l , 2 ] · ( 3 , - 1 , 0 )

A: