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18 grams of Neon gas with a volume of 19 liters at 310K and expands isothermally against a constant external pressure of 9.2 kPa until the volume increases by 4.3 liters. i) Calculate the change in energy of the system due to the work done. ii) Calculate the change in energy from work done if this expansion was instead carried out reversibl iii) Explain why there is a difference in the energy to do the work in parts i) and ii)

18 grams of Neon gas with a volume of 19 liters at 310K and expands isothermally against a constant external pressure of 9.2 kPa until the volume increases by 4.3 liters. i) Calculate the change in energy of the system due to the work done. ii) Calculate the change in energy from work done if this expansion was instead carried out reversibl iii) Explain why there is a difference in the energy to do the work in parts i) and ii)

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter12: Thermodynamic Processes And Thermochemistry
Section: Chapter Questions
Problem 17P
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18 grams of Neon gas with a volume of 19 liters at 310K and expands isothermally against a constant external pressure of 9.2 kPa until the volume increases by 4.3 liters. i) Calculate the change in energy of the system due to the work done. ii) Calculate the change in energy from work done if this expansion was instead carried out reversibly. iii) Explain why there is a difference in the energy to do the work in parts i) and ii)
Transcribed Image Text:18 grams of Neon gas with a volume of 19 liters at 310K and expands isothermally against a constant external pressure of 9.2 kPa until the volume increases by 4.3 liters. i) Calculate the change in energy of the system due to the work done. ii) Calculate the change in energy from work done if this expansion was instead carried out reversibly. iii) Explain why there is a difference in the energy to do the work in parts i) and ii)
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