17. A series RLC circuit has R = 100, L = 40 × 10-6H and C = 60 x 10-12F. What is the resonant of the circuit in MHz?
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- Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor, and a 4 capacitor. (a) Draw the circuit diagram. (b) Compute the series impedance. (C) Determine the current I delivered by the source. Is the current lagging or leading the source voltage? What is the power factor of this circuit?For a given series RC circuit with resistance R= 50 ohm and capacitance C= 1.5uF connected to an ac voltage source of 60V, 2500 Hz, then the magnitude of current through the circuit is Select one: Oa. 3.45A Cb.0915A Oc.None of these O d. 5.45A Next pag umn tr ere to searchFor a given series RC circuit with resistance R= 50 ohm and capacitance C= 1.5uF connected to an ac voltage source of 60 V, 2500 Hz, then the magnitude of current through the circuit is Select one: a. 5.45A b. 3.45A c. 0.915A d. None of these
- A parallel circuit has 10 ohms of resistance and a capacitive reactance of 15 ohms, An ac rms voltage of 200 V isapplied across it. What is the magnitude of the total current?The rms value of the resultant current in a wire carries a dc current of 10 A and a sinusoidal alternating current of peak of value 20 A is-can you please give me the comple solution for this question, thanks. A certain voltage function contains a constant term, a fundamental and third harmonic. The maximum value of the fundamental is 85 % of the constant term and the maximum value of the third harmonic is 55 % of the constant term. If the effective value of this function is 180.3V, find the magnitude of the two harmonics. A.IstHarmonic = 75 V , 3rd Harmonic = 120V B. Ist Harmonic = 80 V , 3rd Harmonic = 125V C. IstHarmonic = 120 , 3rd Harmonic = 75V D. Ist Harmonic = 125 V , 3rd Harmonic = 80V E. NOTA
- Describe the resulting waveforms when the capacitors (initially 20uF and then replaced with 100uF) were connected in parallel with the loadShown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 9.35 Volts and is running at a frequency of f = 113000 Hz. The resistor has a resistance of R = 1980 , the capacitor has a capacitance of C = 1.08e-09 Farads, and the inductor has an inductance of L = 3.71e-03 Henries. mm Vps Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit øztot Determine the numerical value of Ztot = 2384 Determine the numerical value of @Z tot Determine the current through the circuit: ● R www I(PEAK) = I(RMS) = ● ● Determine the voltage across the inductor: • VL(PEAK) = Volts Volts VL(RMS) = Amps Amps Determine the voltage across the capacitor: Vc(PEAK) = Volts Volts Vc(RMS) = = 33.85 a capacitive switcher Ω degrees C If a second circuit were connected in parallel with the resistor, this circuit would be considered as: O a high-pass filter a radio tuner O…Transform from sinusoid to phasor 5cos4t + 7sin4t
- 4. Find Idc, Vdc and the capacitance that will force the Vr(pp) to 2mV. Draw the output waveform across the capacitor. Fin=60HZ. TX1 D1 Ge Vac Lst 230V Lp 1 RL 12-0-12 Center tapped CL 1k D2 Ge 2In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltageDesign a circuit to limit a 20 V rms sinusoidal voltage to a maximum positive amplitude of 10 V and a maximum negative amplitude of -5 Vusing a single 14 V dc voltage source