16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform, CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g) 1 3 is first order in CHCl3, order in Cl₂, and order overall. Show that the following mechanism is consistent with the rate law: (1) Cl₂ (g)=2C1 (g) [fast] (2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g) [slow] (3) CC13 (g) +Cl (g) → CC14 (g) [fast]

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.77QE
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16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform,
CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g)
1
3
is first order in CHCl3,
order in Cl₂, and
order overall. Show that the following mechanism is consistent with the rate law:
(1) Cl₂ (g)=2C1 (g)
[fast]
(2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g)
[slow]
(3) CC13 (g) +Cl (g) → CC14 (g)
[fast]
Transcribed Image Text:16.96 Experiment shows that the rate of formation of carbon tetrachloride from chloroform, CHCl3 (g) + Cl2 (g) → CCl4 (g) + HCl (g) 1 3 is first order in CHCl3, order in Cl₂, and order overall. Show that the following mechanism is consistent with the rate law: (1) Cl₂ (g)=2C1 (g) [fast] (2) C1 (g) + CHCl3 (g) → HCl (g) + CC13 (g) [slow] (3) CC13 (g) +Cl (g) → CC14 (g) [fast]
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