14. II III IV a) The pedigree above shows the passing on of colorblindness. What sex is MOST likely to be carriers of colorblindness? b) Why does individual IV-7 (a female) have colorblindness? c) Why do all the daughters in generation II carry the colorblind gene? d) List two th generation colorblind males. 15. Explain sex linked inheritance with examples. 16. Explain what happens during these following sicknesses and why it happens? i) Sickle cell anemia i Hemophilia 17. What do you understand by the term "Multiple Alleles"? Define the followings: Trait true breeding cross P generation F1 generation monohybrid cross F2 generation dominant recessive law of segregation genotype phenotype homozygous heterozygous test cross dihybrid cross law of independent assortment pedigree autosomal recessive Punnett square autosomal inheritance autosomal dominant 4

14. II III IV a) The pedigree above shows the passing on of colorblindness. What sex is MOST likely to be carriers of colorblindness? b) Why does individual IV-7 (a female) have colorblindness? c) Why do all the daughters in generation II carry the colorblind gene? d) List two th generation colorblind males. 15. Explain sex linked inheritance with examples. 16. Explain what happens during these following sicknesses and why it happens? i) Sickle cell anemia i Hemophilia 17. What do you understand by the term "Multiple Alleles"? Define the followings: Trait true breeding cross P generation F1 generation monohybrid cross F2 generation dominant recessive law of segregation genotype phenotype homozygous heterozygous test cross dihybrid cross law of independent assortment pedigree autosomal recessive Punnett square autosomal inheritance autosomal dominant 4

Name: 14.ii) If Individuals #6 and #7 have another daughter what are the ch
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Description: 14.ii) If Individuals #6 and #7 have another daughter what are the chances that she will be affected.1IIIVa) The pedigree above shows the passing on of colorblindness. What sex is MOST likely to be carriers ofcolorblindness?b) Why does individual IV

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 17CTQ: Can a male be a carrier of red-green color blindness?

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1. A) Apply the concept of sex linkage to explain why color blindness is more prevalent in men than in women. B) Mary is concerned that she may be a carrier for hemophilia, a sex-linked condition located on the X chromosome. Mary is married to John, who doesn't have hemophilia. Assuming Mary is a carrier, what are the genotype ratios expected for Mary and John's kids (specify for boys and for girls)? C) Mary and John have 2 boys, none of them has hemophilia. Can we use this fact as proof that Mary does not carry the allele for hemophilia? Explain your argument.
Consider a couple: a woman who is homozygous for a recessive mutation that causes X-linked colorblindness, and a man with full color vision (he does not carry a copy of the mutation). a) What is the probability that a son of this couple will be colorblind? b) What is the probability that a daughter of the couple will be colorblind?
6) For the pedigree shown below, answer the following questions. I II III a) What type of inheritance is shown? Explain how you know. b) The genotype of individual I -2 is The genotype of individual II -1 is
2. Hemophilia is an X linked recessive trait. There is a woman who is a carrier for hemophilia and marries a man with hemophilia. a) Complete the Punnett Square (it is a google drawing so you will have to double click it to go to the drawing and type in and around the square. Hold the CONTROL (or Command) button and press the PERIOD button to write a superscript/exponent.) b) What are the possible genotypes of the children? c) Could any of their children have hemophilia? If so, would the child be male or female? Explain your reasoning.
The allele for colorblindness is carried on the X chromosome and is recessive. A man, whose father was colorblind, has a colorblind daughter. 1. a) Is this man colorblind? How do you know? b) Where did he get his gene for colorblindness? c) Must the fathers of all colorblind girls be colorblind? Why?
Hypophosphatemia (vitamin D-resistant rickets) is inherited as a sex-linked dominant trait (H). A) A normal woman and a man with hypophosphatemia marry. What is the chance of having daughters with rickets? Sons? B) A heterozygous woman and a normal man marry. Does the mother have rickets? What is the chance of having daughters with rickets? Sons?
A man and his wife are both heterozygous for brown eyes. They have ix children all of whom have blue eyes? A) How is it explained? B) What are the chances that their next child will have brown eyes? C) What are the chances that their next child will have blue eyes.
Given these parents-note, they are NOT quite the same as each other!: mom = Aa Bb Cc Dd dad = Aa Bb cc Dd NOTE that the A gene acts incompletely dominantly. a) What chance does their baby having the "strongest phenotype" in A, being recessive in b, recessive in c, and dominant in D? Give one fraction. Show work. b) phenotype? Now assume mom was CC instead of Cc. Now what is the chance of having that same
6. a) Which individual (what number) in the pedigree below rules out X-linked dominant? b) Which individual in the pedigree below rules out autosomal recessive? Briefly explain why. c) Which individual in the pedigree rules out X-linked recessive? Briefly explain why. 1 2 II 1 2 II 1 2 3 4 5 6 7 8 IV 1
1. Given the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked recessive and b) X-linked dominant in order to determine what is the mode of transmission of this trait. Disease allele = XA or Xa, depending on mode of transmission of the disease respectively. *Unaffected/No carrier-Normal Unaffected X chromosome = X I 11 * 1 2 1 2 3 a) X-linked recessive 11x12 III 2 genotype (circle one): XY 4 XAXA 2 3 5 Xaya *4 6 7 8 b) X-linked dominant 11x12 XAY Xay
12. A heterozygous black mouse is crossed with a white mouse. a) Which color is dominant? b) How did you know? c) Which letter will stand for the dominant color? d) Which letter will stand for the recessive color? e) What is the genotype of the white mouse? f) What is the genotype of the heterozygous black mouse? g) Complete the Punnett Square below for this cross. h) What percent of the offspring will be black?
PKU is an inherited disease caused by a recessive allele. If a woman and her husband, who are both carriers (heterozygotes) for the disorder, have three children, what is the probability of each of the following? a) All three children are of normal phenotype. b) All three children have the disease. c) Any 2 of the three children have the normal phenotype.