13. Draw the Lewis structures and predict the hybridization (sp, sp2, sp³), geometry (linear, trigonal, tetrahedral) and bond angles (180°, 120°, 109.5°) for the central atoms in the following compounds. a. Nin NH3 b. O in H2O d. C and N in CH3CHNH e. C and N in C CH3CN c. Cin CH3CHCHCH3

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Chapter4: Molecular Structure And Orbitals
Section: Chapter Questions
Problem 5RQ: What hybridization is required for central atoms that have a tetrahedral arrangement of electron...
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13. Draw the Lewis structures and predict the hybridization (sp, sp?, sp³),
geometry (linear, trigonal, tetrahedral) and bond angles (180°, 120°, 109.5°)
for the central atoms in the following compounds.
a. Nin NH3
b. O in H2O
d. C and N in CH3CHNH
e. C and N in C CH3CN
c. Cin CH3OCHCHCH3
14. Which of the following compounds show cis-trans isomerism? Draw the cis
and trans isomers of those that do.
a. CHF=CHF
b.
c. F2C=CH2
CHCH3
15. Identify whether the following pairs of structures are: (A) Same compound,
(B) Constitutional isomers, (C) Cis-trans isomers or (D) Not isomers.
a. (i)
CH,CH,CHCH,CH, and CH,CH,CHCH,CH,CH,
1.
(i)
1,
CH3
CH̟CH,
b. (i)
Br
(i)
Br
H
Br
and
Br
H
(ii)
H.
С.
(i)
Br.
Br.
C=
and
H
Br
Br
H.
d. (i)
Br.
(ii)
H.
H
Br
C=
and
H
Br
Br
H.
(i)
(ii)
Cl Cl
е.
H Cl
Н—С—С—Н
and
Н—С—С—Н
ČI H
нн
Transcribed Image Text:13. Draw the Lewis structures and predict the hybridization (sp, sp?, sp³), geometry (linear, trigonal, tetrahedral) and bond angles (180°, 120°, 109.5°) for the central atoms in the following compounds. a. Nin NH3 b. O in H2O d. C and N in CH3CHNH e. C and N in C CH3CN c. Cin CH3OCHCHCH3 14. Which of the following compounds show cis-trans isomerism? Draw the cis and trans isomers of those that do. a. CHF=CHF b. c. F2C=CH2 CHCH3 15. Identify whether the following pairs of structures are: (A) Same compound, (B) Constitutional isomers, (C) Cis-trans isomers or (D) Not isomers. a. (i) CH,CH,CHCH,CH, and CH,CH,CHCH,CH,CH, 1. (i) 1, CH3 CH̟CH, b. (i) Br (i) Br H Br and Br H (ii) H. С. (i) Br. Br. C= and H Br Br H. d. (i) Br. (ii) H. H Br C= and H Br Br H. (i) (ii) Cl Cl е. H Cl Н—С—С—Н and Н—С—С—Н ČI H нн
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