13- If you were to have a mythical AA based on Aspartic acid in which the carboxylate on the side chain is replaced by a hydroxyl (alcoholic) group with pKa of 15.0. What would be the predominant form of this AA at pH 1, 7 and 12?
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- n5of 15 > Glycine is a diprotic acid, which can potentially undergo two dissociation reactions, one for the a-amino group (–NH;), and the other for the carboxyl (–COOH) group. Therefore, it has two pK, values. The carboxyl group has a pKj of 2.34 and the a-aminc group has a pK2 of 9.60. Glycine can exist in fully deprotonated (NH, –CH, –COO"), fully protonated (NH† –CH, -COOH), or zwitterionic form (NH;-CH,-CO0-). Match the pH values with the corresponding form of glycine that would be present in the highest concentration in a solution of that pH. fully deprotonated form fully protonated form zwitterionic form NH,–CH,-COO" NH; –CH,-COOH NH -CH, -COO- Answer Bank pH 7.0 pH 1.0 pH 8.0 pH 11.9 PН 6.0 MacBook Air DII DD F4 F5 F6 F7 F8 F9 F10 F11 F12 $ & * 4 5 6. 7 8. R T. Y U %D F H J K + || * 00 %24OF as fil PDF What are the products of the reaction of the triacylglycerol found in coconut oil (containing only lauric acid) with KOH? O UNOFFIC TRANSCR 9°F Mostly cloudy CH,−O–C−(CH2)10—CH3 0 CH-0-C-(CH₂)10-CH3 + 3KOH O CH,−O−C(CH2)10—CH3 Glyceryl trilaurate O one glycerol molecule and three potassium laurate formula units O one glycerol molecule and three sodium laurate formula units O one glycerol molecule and three lauric acid molecules O one glycerol molecule and three potassium myristate formula units A Heat, 10 O Search ac PD PD maste omiss pe huniz recor C21-43 Give appropriate names for the following compounds: (а) (b) (с) CH;CH,CH,CH2 -C-ci Ph CH, CH,CH-C-N-Ph (d) (e) () H. CH3CH N-ċ-Ph CH3CH,-Č-0-Ph CH3CH 0-C-Ph (g) hoonon (h) (1) CH;CH,O OCH CH, (G) (k) (1) H,C CH- C-N(CH,CH3)2 H;C O.
- Which of the following bases are strong enough to deprotonate C6H5OH (pKa = 10) so that equilibrium favors the products: (a) H2O; (b) NaOH; (c) NaNH2; (d) CH3NH2; (e) NaHCO3; (f) NaSH; (g) NaH?10) The drug hydroxychloroquine has three amino groups, identify each as 1º, 2°, or 3°, and whether they are aliphatic, aromatic, or heterocyclic. OH HN Hydroxychloroquine is used as the sulfate salt, why?If an acid with a pK₂ of 5.0 is in an aqueous solution of pH = 5.5, what percentage of the acid is present in its acidic form? Express your answer using two significant figures. ΑΣΦ pH = ? At what pH will 75% of the acid exist in its acidic form? Express your answer using one decimal place. 5 ΑΣΦ % ?
- A biochemist completely digests a glycerophospholipid with a mixture of phospholipases A and D. HPLC and mass spectrometry analysis reveals the presence of an amino acid of 105,09 Da, a saturated fatty acid of 256.43 Da, and an omega-3 monounsaturated fatty acid of 282.45 Da. Which amino acid does the glycerophospholipid contain? O valine (C,H, NO,) O alanine (C, H,NO,) O scrine (C,H,NO,) O proline (C,H,NO,) Modify the phosphoglycerol backbone to draw the most likely structure of the lipid. Add the amino acid using the groups tool. Draw Rings Groups More Erase Select78 Write the expected products of the acid hydrolysis of the following tetrapeptide: byd to joile sdi at Jad W Ca 10 O (701 || H₂N-CH-C-N-CH-C-N-CH-C-N-CH-C-0- ENCHEN CHEO H CH₂ H CH,-C-NH + | H₂C-CH | CH₂ T | | H CH₂ H N-Both norepinephrine and epinephrine are synthesized from the same protein-derived amino acid. From which amino acid are they synthesized? What types of reactions are involved in their biosynthesis? н он H OH H HO. NH, НО. CH3 (a) (b) HO НО Norepinephrine Epinephrine (Adrenaline)
- Identify the following antioxidant molecule. A. alpha tocopherol hydroquinone B.dehydroascorbic acid CH3 CH3 C. alpha tocopherol semi-quinone \ / D. ascorbic acid C = C E. alpha tocopherol quinone / \ : O – C C – O CH3 \\ // \ / C – C C – CH2–CH2–CH2–CH–CH2–CH2–CH2–CH–CH2–CH2–CH2–CH–CH3 / \ / l l l CH3 CH2– CH2…See Appendix on p5 for list of amino acids. Aspartame is a sweetener. The structure of aspartame, along with the titration curve showing its pKal and pka2 is given below. 14 € 12 10 8 6 4 2 0 pK₂2 = 7.87 PK₁₁ = 3.19 0 0.5 1 Equivalents of NaOH a) Copy the structure of aspartame. i) 1.5 2 OH S NH₂ Aspartame LOCH 3 Identify the two ionisable groups. Re-draw the groups in their protonated forms, and label each with their pka. ii) Circle and identify the two amino acids in aspartame.Below is the structure of eicosapentaenoic acid (EPA) which is an omega-3 fatty acid. What would be the IUPAC (International Union of Pure and Applied Chemistry) designation (the nomenclature emphasized in lecture) for EPA? omega-3 20:4 (A5,8,11,14) 20:5 (43,6,9,12,15) 20:0 20:5 (A5,8,11,14,17) ◄ Previous Il app.honorlock.com is sharing your screen. Stop sharing Hide Your Webcam
