12. complete the following transformations A. 1. 2. COOH C. 1. Br 2. D. он HO. Br F. 1. 2. G. CH, .CI (CH,CH,),CuLi Ether, -78 °C H. Me L 2 CH,I
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- Ď 1. a. C. t X x НО OH Cro3 Hs04 SOCI 1. MCPBA 2. CH3 CH₂ Mg Br THF 3. Hcl Workup PCC CH₂ C12 ←b. Table 4.1 shows the displayed formulae and boiling points of four hydrocarbons, A, B, C and D. A B с D Table 4.1 displayed formula HHHHHH |||||| H-C-C-C-C-C-C-H H 1 H H H H H HHHH H-C-C-C-C-H I II H HHH HHHH HIC-CIC=C-H 1 H H H H HHHH I H-C-C-C-C-C-C-H |||| HHHH boiling point/°C 69 -0.5 -6.3 63 i. Name the two homologous series to which the hydrocarbons in Table 4.1 belong. and ii. Use the information on Table 4.1 to suggest one way in which the boiling point of a hydrocarbon is affected by its molecular structure. iii. A bottle contains a colourless liquid which is thought to be either hydrocarbon A or D. Describe a chemical test, and its results, which could be used to identify which hydrocarbon is in the bottle. Explain your choice of test.OCH3 NH₂ CH3- OH 1. CH₂MgBr 2. H3O+ NH AICI 3 CI .&M H ze bes AICI3 1. excess CH3l 2. Ag₂O, H₂O 3. heat heat 1. Br2, PBr3 2. H₂O Hg, Zn, HCI 1. KOH 2. CI 3. KOH, H₂O, heat CH3 blank 1 blank 2 blank 3 blank 4 blank 5 blank 6 blank 7 blank 8 blank 9 1. KOCH3 2. H₂O, H+, heat blank 10 O-+K OH OH CH3CH₂Br NH,NH2, KOH H+ H₂, Pd DMSO, (COCI) 2 Et3N NaNH, NH3 Ag(NH3)2* KOH, H₂O KOH, heat PPh3 excess CH3OH H+ blank 11 blank 12 blank 13 blank 15 blank 14 blank 16 blank 17 blank 18 blank 19
- a) 4-Pentenoic acid + H, KMn04 / OH B 0-10°C NaBH4 b) CH,=CH-CH,-CH,-C -Co,H Mg Co c) 5-Chloro-1-pentene Etz0 Br2 Na,Cr0, d) Toluene CH;Br H3o*, heat F CyH-Bro Fe Na,Cr,0, H30*, heatWhat are the best reagents to effect each of the steps below?©GMU 2020 A H3C CH3 CH3 H3C HO CH3 CH3 H3C CH3 CH3 F НО H3C CH3 CH3 H3C CH3 CH3Study questions -chapt 18 1. Which of the following changes lead to a decrease in entropy? a. sugar dissolving in coffee b. mixing of pure gases c. the sublimation (vaporization) of dry ice (solid carbon dioxide) d. melting snow e. halving the volume of a gas 2 At what temperatures will a reaction be spontaneous if A,H° = +117 kJ and A,S° =-35 J/K? 3. Calculate A,G° for the following reaction at 425 °C, (8)I + (3)*H_, (3)IH given K= 0.018. (R=8.314 J/K-mol) %3D 4. For a reaction, A,H° = -208.8 kJ and A,S° =-308.2 J/K. At what temperature will A,G° = 0.00 kJ? %3D %3D 5. What is the sign of AH (system) and AS (system) if a chemical reaction is spontaneous at all temperatures under standard conditions? HV ε (system) is negative, and AS (system) is positive. HV °q (system) is negative, and AS (system) is negative. HV (system) is positive, and AS (system) is positive. HV P (system) is positive, and AS (system) is negative. e. none of these 6. For which of the following reactions will the…
- A edu.co g Ce... Aktiv Chemistry $ R F5 Hess's law can be used to solve for reaction enthalpy changes because enthalpy is a function. ► 11 k % 5 F6 6 + A) path B) state C) thermodynamic F7 D) pressure-volume Question 8 of 12 F8 & 7 F9 * 8 P 1 K F10 ( 9 F11 O F12 P PrtScr "Kº ( + Insert 604x Delete O PgUpOH Br OH OCH₂ H 1. DIBAL-H 2. H₂O+ 1. PPh3 2. nBuLi cat. H*A* excess NaOCH3 Br- Br NH,NH2 KCN HCN KOH HeatO Me 'Me 1. Br₂, hv, CCl4 2. Mgº, Et₂0 3. HCI, H₂O 4. conc. H₂SO4, heat 1. n-PrMgBr (excess) 2. TsCl, pry., 0 °C 3. NAOMe
- Vames and Ti... V At Your Service Inte... Sy log_{b}sqrt(b) - Sim... O (Last Day Promotio.. Kronos Workforce... Maame Acheampo.. MIDTERM MODER... [References] In a coffee-cup calorimeter, 100.0 mL of 1.1 M NAOH and 100.0 mL of 1.1 M HCl are mixed. Both solutions were originally at 20.3°C. After the reaction, the final temperature is 27.7°C. Assuming that all the solutions have a density of 1.0 g/cm" and a specific heat capacity of 4.18 J/°C g, calculate the ethalpy change for the neutralization of HCl by NaOH Assume that no heat is lost to the surroundings or to the calorimeter. AH= kJ/mol Submit Answer Try Another Version 1 item attempt remaining Previous Next, 8:31 PM 1へ梦口后会 12/5/2020 hingThe value of An, in the combustion reaction of methane is CH4(g) + 202 (g) CO2(g) + 2H,0 (g) О а. 1 O b. 2 Ос. -2 O d. 0d. |||||| CO₂K 1. 12, CH3CN, -15 °C 2. BnOK, THF, -20 °C D