What is the IR and HNMRAndCNMR and mass IR Spectrum(KBr disc)400010080% of base peak300056408013C NMR Spectrum(100 0 MHz. CDCI, solution)DEPT CH₂ CH₂ CHproton decoupled200¹H NMR Spectrum(400 MHz, CDCI, solution)109871693v (cm³)O120 160m/e2000M-1121607160061200120800Mass SpectrumC6H8O₂280200 2405solvent804Problem 10M = 12+2(0₂14-8 = 6=3C=0₂No significant UVabsorption above 220 nm2X6 + 2 (8-2) 1 (E12+2-(6) +4=16/20340211618 (ppm)TMSL08 (ppm)

DEPT is distortionless Enhancement by Polarization Transfer. It is one type of NMR.

100 80 IR Spectrum (KBr disc) 4000 % of bane peak 3000 5 20 40 80 13C NMR Spectrum (100 0 MHz. CDCI, solution) DEPT CH, CH₂ CH proton decoupled 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 10 9 8 1693 v (cm³) 0 120 160 m/e 2000 M-112 160 7 1600 6 1200 120 800 Mass Spectrum C6H80₂ 280 200 240 5 solvent 80 4 Problem 10 M= 12+2 (0₂14-8 = C=0₂ No significant UV absorption above 220 nm 2*6 +2 (8-2) + 12+2 (6) 4 =16/6 0 8 (ppm) TMS L 0 8 (pp 3 40 2 11 J 1 L

100 80 IR Spectrum (KBr disc) 4000 % of bane peak 3000 5 20 40 80 13C NMR Spectrum (100 0 MHz. CDCI, solution) DEPT CH, CH₂ CH proton decoupled 200 ¹H NMR Spectrum (400 MHz, CDCI, solution) 10 9 8 1693 v (cm³) 0 120 160 m/e 2000 M-112 160 7 1600 6 1200 120 800 Mass Spectrum C6H80₂ 280 200 240 5 solvent 80 4 Problem 10 M= 12+2 (0₂14-8 = C=0₂ No significant UV absorption above 220 nm 2*6 +2 (8-2) + 12+2 (6) 4 =16/6 0 8 (ppm) TMS L 0 8 (pp 3 40 2 11 J 1 L

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) C₂H₂ NO ₂ expansion 3.0 160 2.0 120 1.0 ppm 10 9 8 7 6 Determine the structure of the compound 5 solvent 80 4 40 3 2 08 (ppm) 1 TMS 0 8 (ppm)
4000 100 80 60 20 % of base peak 3376 40 10 3000 59 13C NMR Spectrum (50.0 MHz, CDCI, solution) 173 proton decoupled 200 I 9 80 ¹H NMR Spectrum (200 MHz, CDCI, solution) DEPT CH₂ CH₂ CH4 IR Spectrum (liquid film) 2000 M+88 (<1%) 120 1600 v (cm¹) m/e 160 160 I I 8 7 mmm 1 120 200 240 6 1200 . Mass Spectrum L 800 1 5 C5H₁20 280 solvent L 80 4 problem 78 3 No significant UV absorption above 220 nm 40 Il 08 (ppm) 1 2 1 TMS 0 8 (ppm)
IR Spectrum (liquid film) 4000 100 80 زار 60 40 20 stelldefels % of base peak 3000 40 57 91 13C NMR Spectrum (50.0 MHz, CDCI, solution) 92 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 1 2000 V (cm¹) 8 80 120 160 k 160 M+ m/e M 148 7 1600 200 IL 6 120 800 Mass Spectrum C11H16 280 solvent J 1200 240 expansion 7.5 I 1 5 L 80 7.0 I 4 1 ppm 3 Problem 97 UV Spectrum max 260 nm (log10 2.5) solvent methanol 40 I 2 0 1 8 (ppm) TMS L 0 8 (ppm) 203
4000 100 80 60 40 20 3410 tele 3000 40 10 43 ¹3C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 6.0 DEPT CH, CH₂ 1 CH 1 9 71 80 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) expansion ORGANIC STRUCTURES FROM SPECTRA 5.5 8 IR Spectrum (liquid film) 2000 M 86 (1%) 120 V (cm) m/e 160 1600 7 160 200 5.0 ppm 6 120 1200 J Mass Spectrum 240 800 5 CsH10O 280 solvent 80 4 exchanges with D.O 1 L 3 40 No significant UV absorption above 220 nm 2 E Q 115 08 (ppm) 1 TMS L 0 ō (ppm) IR: List bands and possible/probable structural units responsible Band (cm³) Possible stretches/functional groups MS: Molecular Formula, 13C NMR: 1 2 3 4 5 6 Chem. Shift (8) Type of C (sp), sp², carbonyl, etc.) ¹H NMR: 1 Chem. Shift (8) Multiplicity (singlet, doublet, etc.) IHD(DU)= 2 3 4 5 6 If you need more space, add any additional signal info here: (Show calculation) # of attached H's # of identical C's in signal Probable Type of H (methyl, aromatic, etc.) # of identical H's in signal
9 ¹H-NMR Spectra 2 M.F. = C₁₁H₁2O 15 15 -00 8 15 15 7 1 S 6 O) 15 15 5 PPM 4 21 -♡ 3 2 3) 0
A student performed a series of reactions and obtained the spectral data provided. The reaction sequence is shown below.. What are the structures for A, B, C, and D? Compound B NMR (relative integrated areas below peaks) CH;CH,O°N 1. BHTHF N-bromosuccnimide A CH;CH,OH B 2. H,O,/OH- D hv reflux Compound A NMR (relative integrated areas below peaks) PPM 5 Compound B IR INFRARED SPECTRUM PPM 5 1 6 0.8 Compound A IR INFRARED SPECTRUM 0.6 0.8 0.4 0.4 0.2- 3000 2000 Wavenumber (cm-1) 1000 The MS of compound B shows an M+ peak at 198 and an M+2 peak at 200 with a relative abundance of 1:0.97 2000 Wavenumber (cm-1) 3000 1000 Transmitance Relative Transmittance
¹3C NMR Spectrum (CDCI, 25MHz, ¹ H decoupled, solvent signals removed for clarity) Not sure how to interpret this C NMR. The molecular formula is C9H100 200 13C NMR Spectrum (CDCI3, 25 MHz, ¹H decoupled, solvent signals removed for clarity) d S 180 160 140 120 Ć 100 ppm 80 60 40 20 0
4000 IR Spectrum quid film) 100 80 60 40 YI 2248 41 10 3000 43 40 proton decoupled "C NMR Spectrum (150 MHz CDC, solution) 68 DEPT CH, CH, 1 CHT 9 200 ¹H NMR Spectrum (600 MHz, CDC, solution) M83 (<1%) 80 120 2000 v (cm) 8 m/e 160 160 2.3 L 7 1600 2.2 200 ryper 1200 6 ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ 120 Mass Spectrum 240 21 2.0 expansions (not to scale) 800 I CsH₂N 280 5 expansion 80 4 270 255 256 255 expansion No significant UV absorption above 220 nm 27.0 245 250 255 1.0 3 40 L 2 0 8 (ppm) 1 1 TMS L 1 0 8 (ppm) 10 ¹H-¹C me-HSQC Spectrum (600 MHz, CDC, solution) Black cross-peaks CH and CH Red cross-peaks CH₂ ppm 20 ¹H-"C HMBC Spectrum (600 MHz, CDC), solution) -22 -24 -26 -28 116 118 120 122 124 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 ppm ppm 20 22 -24 26 28 -116 118 -120 122 -124 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0.6 ppm IR: List bands and possible/probable structural units responsible Band (cm³) Possible…
опанит 1715 1600 IR Spectrum 100 4000 (liquid film) 43 80 75 60 M 40 20 % of base peak 10 3000 40 C 13C NMR Spectrum (20.0 MHz, CDCI solution) proton decoupled 9 80 200 ¹H NMR Spectrum (100 MHz, CDCI, solution) 101 8 2000 v (cm¹) M** 132 120 160 m/e 160 7 6 1200 120 Mass Spectrum 200 240 280 800 C-H 5 C6H1203 solvent L 80 4 -CH3 No significant UV absorption above 220 nm 3 H-C-H u -CH3 40 2 59 TMS 0 1 8 (ppm) TMS 0 8 (ppm)
13C NMR Spectrum (100.0 MHz, D20 solution) CgHgNO3 DEPT proton decoupled 200 160 120 80 40 O 8 (ppm) 'H NMR Spectrum (400 MHz, D20 solution) expansions Note: there are 4 protons which exchange with the D20 solvent 4.3 4.1 ppm 3.6 3.4 ppm 1.3 1.1 ppm HаО and HOD in solvent 8 7 6 4 3 2 1 8 (ppm) 10 9 Determine the structure of the compound.
7.) From the following sets of data, please propose a reasonable structure for the unknown organic compound. This molecule is entirely composed of C, H, and N only. Please show all of your work and feel free to write on the spectra any clues as to the structure. 4000 3000 2000 1000 S DO Infrared spectrum of unknown. KBr salt plate sample. 100 MS-NU-6396 80 60 40 20 - 10 20 30 40 50 60 70 80 90 100 110 m/z Mass spectrum of unknown. Molecular ion = 83.1 Relative Intensity
(f) C10H13NO2 4000 100 80 60 20 % of base peak 3284 43 3000 40 10 IR Spectrum (KBr disc) proton decoupled 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH₂ CH₁ CH 200 9 80 ¹H NMR Spectrum (200 MHz, CDCI, solution) exchanges with D₂O on warming 108 le 137 M+* 179 120 160 2000 8 1658 v (cm¹) 1600 m/e 1 160 if L 7 120 expansion 1200 6 200 240 280 7.6 800 Mass Spectrum C10H13 NO₂ 5 solvent 80 l 7.0 4 ppm UV Spectrum max 250 nm (log₁0€ 3.1) A max 287 nm (log₁0 2.2) solvent: chloroform 3 40 2 0 1 8 (ppm) TMS 0 8 (ppm)