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- Fill in all the missing values. Refer to the formulas that follow. Resistance Capacitance Time constant Total time 150 k 100 F 350 k 35 s 350 pF 10 s 0.05 F 1.2 M 0.47 F 12F 0.05 s 86 k 1.5 s 120 k 470 pF 250 nF 100 ms 8 F 150 s 100 k 150 ms 33 k 4 F =RCR=CC=R Totaltime=5Find: Ib, Ic, Vce, Vb, Vc, Vrb Vre, & Vrc Note: show your solutions no solution means wrong answers. C2 HE 1000μF Rb 560 ΚΩ VCC 12V Rc 2kQ Q1 C1 요 HE 1000μF 2SC1815 R1 2000Discussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°
- What is the total equivalent (total) inductance Lr of this circuit? 000 30mH L2 R 000 60mH 1 kQ 10 V L3 100mH 000 500mH 43 mH 720 mH O 173 mH o 日 点四RUA 36% DE 40°F PriSc Impr. Écr. F12 F10 F11 F7 F8 F9 F4 F5 F6 * & 3 0 1/4 1/2 4. 5 6. 7 8 2 R Y K LDiscussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 μF R Total 10+j0 Volts 10 Z0° 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°Discussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m+ j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 52 0° 26.5258 Z-90° 26.993 Z-79.325° N
- Question 13 For the circuit shown, the following mesh currents are given: IA =1.24271.2° A IB =0.45Z49.0° A Ic = 0.75Z150.2° A What is the value of the voltage VB? j5n + 20 VB 62- 45° V j4 N VA 240° V Vc 5230° V O 2.484- 108.8° V O 2.48471.2 V O 2.23/66.8° V O 2.23Z- 113.2° VDiscussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 µF R C Total 10 + j0 V Volts 10 Z0° 68.623m + j364.06m Amps 370.5m Z 79.325° 5+ j0 52 0° 5 - j26.5258 26.993 Z-79.325° 0 - j26.5258 Ohms 26.5258 Z-90°Find equivalent capacitance for the following: a) C1 AHHHH C2 C3 C4 1µF 2µF 3uF 4µF b) C5 C9 1pF C6 2µF C10 3µF C7 4uF C11 5uF C8 6uF C12 A 7uF 8uF C29 с30 С35 C36 С37 С38 HHHH A С39 C32 42µF 42µF 1µF 2uF 3µF 4uF SuF 10μF C40 C31 C33 6pF 9uF C41 C34 ZuF 10μF C42 C43 8pF 8pF B. HHHHH
- +5V VDO EN Xtal 8ה 7 +5V Freq1 HGND | GND х Mhz Sensor0 crystal Freq26 5 Vss Out 04 PRE Xtal 1k Output HA7210IP 4 CLK CLR SN74HC7491 GND 0.01 μ GND +5V 4 +5V +5V +5V OE O/P3 0. 1µF | 47µF GND SG351P |2 x MHz GND GND Consider the Quartz Crystal Microbalance Sensor shown above, with crystal resonant frequency, x = 3.3 Mhz. You are given the following values: Active crystal area = 1.6 cm², and the change in frequency = - 10 Hz Calculate the change in mass, Am in nano gram, up to 2 decimal places. Answer:9 62 802 5 mH 一 80V 156 1oov o=t エ has been n positien it moves to position The Switeh n the civauit in for a log time. At +=0 b. Find reltl for t70.Solve the following circuit applying Kirchhoff's laws Ri Ry Rz 2K 1.5K 30V E3