10. An artist must push with a minimum force of 75 N at an angle of 45° to a picture to hold it in equilibrium. The coefficient of friction between the wall and the picture frame is 0.30. What is the mass of the picture? Σ Fx = FN - Fx = 0 F=75N Fx = FN = 75 cos 45 = 53.ON Ff F=75 N

Glencoe Physics: Principles and Problems, Student Edition
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ISBN:9780078807213
Author:Paul W. Zitzewitz
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Chapter5: Displacement And Force In Two Dimensions
Section: Chapter Questions
Problem 82A
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HELP! I am new to this so can you please provide an explanation on what this means and show the answer by plugging in the numbers while solving It would help a lot! Thank you!
10. An artist must push with a minimum force of 75 N at an angle of 45° to a picture to hold it
in equilibrium. The coefficient of friction between the wall and the picture frame is 0.30.
What is the mass of the picture?
Σ Fx = FN - Fx = 0
F= 75N
Fx = FN = 75 cos 45 = 53.0N
Σ Fy = Fy + F₂ - 5 = 0
Fg = Fy + Ff = Fy + M FN
A.
1.6 kg
B.
2.3 kg
C.
3.8 kg
D
7.0 kg
=
= 75 sin 45+ (0.30) (53.0)
68.9N
m=
g
Fx
=
=
7.0ky
Ff
F=75 N
FN
101 1
Transcribed Image Text:10. An artist must push with a minimum force of 75 N at an angle of 45° to a picture to hold it in equilibrium. The coefficient of friction between the wall and the picture frame is 0.30. What is the mass of the picture? Σ Fx = FN - Fx = 0 F= 75N Fx = FN = 75 cos 45 = 53.0N Σ Fy = Fy + F₂ - 5 = 0 Fg = Fy + Ff = Fy + M FN A. 1.6 kg B. 2.3 kg C. 3.8 kg D 7.0 kg = = 75 sin 45+ (0.30) (53.0) 68.9N m= g Fx = = 7.0ky Ff F=75 N FN 101 1
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