1. Students will show works for this problem to receive credits: A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is the force of friction acting on the box? (Ff=u x En), (Fn=-Fg), (Fg%3Dmass x-9.81). P =mxv p= momentum m=mass V= velocity Directly proportional vs Inversely Proportional: When two variables are on different sides of the equal sign ( the equation), -if they are both on top of the fraction or both on the bottom of the fraction - directly proportional (Fc and m)( Fc and Vt) -if one is on the top of the fraction, one is on the bottom (Fc and r) inversely proportional

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 2.9CYU: Check Your Understanding Suppose that Balto in Example 2.10 leaves the game to attend to more...
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BIUA
三 三
1
3
5 |II 6 I
1. Students will show works for this problem to receive credits:
A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of
kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is
the force of friction acting on the box? (Ff=u x Fn), (Fn=-Fg), (Fg%3Dmass x-9.81).
P = m x v
p= momentum
m=mass
V= velocity
Directly proportional vs Inversely Proportional:
When two variables are on different sides of the equal sign ( the equation),
-if they are both on top of the fraction or both on the bottom of the fraction-
directly proportional (Fc and m)( Fc and Vt)
-if one is on the top of the fraction, one is on the bottom - inversely proportional
(Fc and r)
When two variahles are on the same sides of the egual sign
III
Transcribed Image Text:You've already resp.. Tylon Clark-Algebr. Copy of Tylon Clark.. M escribing ons Help Last edit was 3 minutes ago rial 12 BIUA 三 三 1 3 5 |II 6 I 1. Students will show works for this problem to receive credits: A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is the force of friction acting on the box? (Ff=u x Fn), (Fn=-Fg), (Fg%3Dmass x-9.81). P = m x v p= momentum m=mass V= velocity Directly proportional vs Inversely Proportional: When two variables are on different sides of the equal sign ( the equation), -if they are both on top of the fraction or both on the bottom of the fraction- directly proportional (Fc and m)( Fc and Vt) -if one is on the top of the fraction, one is on the bottom - inversely proportional (Fc and r) When two variahles are on the same sides of the egual sign III
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