1. Students will show works for this problem to receive credits: A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is the force of friction acting on the box? (Ff=u x En), (Fn=-Fg), (Fg%3Dmass x-9.81). P =mxv p= momentum m=mass V= velocity Directly proportional vs Inversely Proportional: When two variables are on different sides of the equal sign ( the equation), -if they are both on top of the fraction or both on the bottom of the fraction - directly proportional (Fc and m)( Fc and Vt) -if one is on the top of the fraction, one is on the bottom (Fc and r) inversely proportional
1. Students will show works for this problem to receive credits: A 25 kg wood box is sliding across a wood surface, experiencing a coefficient (u) of kinetic friction of 0.20. The box is experiencing an applied force of +63 Newtons. What is the force of friction acting on the box? (Ff=u x En), (Fn=-Fg), (Fg%3Dmass x-9.81). P =mxv p= momentum m=mass V= velocity Directly proportional vs Inversely Proportional: When two variables are on different sides of the equal sign ( the equation), -if they are both on top of the fraction or both on the bottom of the fraction - directly proportional (Fc and m)( Fc and Vt) -if one is on the top of the fraction, one is on the bottom (Fc and r) inversely proportional
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 2.9CYU: Check Your Understanding Suppose that Balto in Example 2.10 leaves the game to attend to more...
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