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1. Show that (a) (1+i)'= exp P(+2x) exp (112) 1 (b) i2i (- 4 = exp[(4n+1)л] (n = 0, ±1, ±2,...). (n = 0, ±1, ±2,...); Section 37 la) Show that (1+i)'= exp(- +2 nπT) exp (i (2) (0 (+7322) Proof (1+;) in Polar form: r = √12²+12 = √2 0 = arctum (+) = tun" " (1) = HT (1+i) = √√2 (cos() + is in (1) (n=12122) (1+i) in exponentul form using Euler's formula? (1+i) = √√2 et #) (1+i); = eiloy (√2e) ei i log (√2 e₁ =) = ; (Inll√zei =)) + Arg (√2017)) = illn (√2) +1 (4+2πh)) = ihn (12) - (+2πh) (4 So (1+i)' = @ilm (√2) - ( + 2πh) = V e - (+2πn) in (√2) e e- (= +2πth) eien (2)

1. Show that (a) (1+i)'= exp P(+2x) exp (112) 1 (b) i2i (- 4 = exp[(4n+1)л] (n = 0, ±1, ±2,...). (n = 0, ±1, ±2,...); Section 37 la) Show that (1+i)'= exp(- +2 nπT) exp (i (2) (0 (+7322) Proof (1+;) in Polar form: r = √12²+12 = √2 0 = arctum (+) = tun" " (1) = HT (1+i) = √√2 (cos() + is in (1) (n=12122) (1+i) in exponentul form using Euler's formula? (1+i) = √√2 et #) (1+i); = eiloy (√2e) ei i log (√2 e₁ =) = ; (Inll√zei =)) + Arg (√2017)) = illn (√2) +1 (4+2πh)) = ihn (12) - (+2πh) (4 So (1+i)' = @ilm (√2) - ( + 2πh) = V e - (+2πn) in (√2) e e- (= +2πth) eien (2)

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 51E
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Can you correct what I did wrong in part a? 

1. Show that (a) (1+i)'= exp P(+2x) exp (112) 1 (b) i2i (- 4 = exp[(4n+1)л] (n = 0, ±1, ±2,...). (n = 0, ±1, ±2,...);
Transcribed Image Text:1. Show that (a) (1+i)'= exp P(+2x) exp (112) 1 (b) i2i (- 4 = exp[(4n+1)л] (n = 0, ±1, ±2,...). (n = 0, ±1, ±2,...);
Section 37 la) Show that (1+i)'= exp(- +2 nπT) exp (i (2) (0 (+7322) Proof (1+;) in Polar form: r = √12²+12 = √2 0 = arctum (+) = tun" " (1) = HT (1+i) = √√2 (cos() + is in (1) (n=12122) (1+i) in exponentul form using Euler's formula? (1+i) = √√2 et #) (1+i); = eiloy (√2e) ei i log (√2 e₁ =) = ; (Inll√zei =)) + Arg (√2017)) = illn (√2) +1 (4+2πh)) = ihn (12) - (+2πh) (4 So (1+i)' = @ilm (√2) - ( + 2πh) = V e - (+2πn) in (√2) e e- (= +2πth) eien (2)
Transcribed Image Text:Section 37 la) Show that (1+i)'= exp(- +2 nπT) exp (i (2) (0 (+7322) Proof (1+;) in Polar form: r = √12²+12 = √2 0 = arctum (+) = tun" " (1) = HT (1+i) = √√2 (cos() + is in (1) (n=12122) (1+i) in exponentul form using Euler's formula? (1+i) = √√2 et #) (1+i); = eiloy (√2e) ei i log (√2 e₁ =) = ; (Inll√zei =)) + Arg (√2017)) = illn (√2) +1 (4+2πh)) = ihn (12) - (+2πh) (4 So (1+i)' = @ilm (√2) - ( + 2πh) = V e - (+2πn) in (√2) e e- (= +2πth) eien (2)
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