1. Ethanol (C₂H5OH) is produced from the fermentation of sucrose (C12H12011) in the presence of enzymes. Determine the theoretical yield and the percent yield of ethanol if 684 g of sucrose undergoes fermentation and 349 g ethanol is obtained. C12H22011 (aq) + H₂0 (g) → 4 C₂H5OH (1) + 4 CO₂ (g)

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter3: Chemical Reactions
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1. Ethanol (C₂H5OH) is produced from the fermentation of sucrose (C12H12011) in the presence
of enzymes. Determine the theoretical yield and the percent yield of ethanol if 684 g of sucrose
undergoes fermentation and 349 g ethanol is obtained.
C12H22O11 (aq) + H₂0 (g) → 4 C₂H5OH (1) + 4 CO₂ (g)
Transcribed Image Text:1. Ethanol (C₂H5OH) is produced from the fermentation of sucrose (C12H12011) in the presence of enzymes. Determine the theoretical yield and the percent yield of ethanol if 684 g of sucrose undergoes fermentation and 349 g ethanol is obtained. C12H22O11 (aq) + H₂0 (g) → 4 C₂H5OH (1) + 4 CO₂ (g)
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