1. DIY Pattern (from codeChum, modified) by Catherine Arellano Step right up and create the pattern! Whoever gets all patterns right will be crowned the new King of Patterns and gets to brag about it to their friends. Here are the instructions: you will be given 4 numbers; each number corresponds to the amount of times a symbol is repeated in the pattern. That's pretty much it. Good luck! Symbols: n1 = # n2=\ n3 = / n4=_ Implement the following functions: int getNum(); /*accepts input from the user."/ void display (int n, int n2, int n3, int n4); /*displays the given pattern/
1. DIY Pattern (from codeChum, modified) by Catherine Arellano Step right up and create the pattern! Whoever gets all patterns right will be crowned the new King of Patterns and gets to brag about it to their friends. Here are the instructions: you will be given 4 numbers; each number corresponds to the amount of times a symbol is repeated in the pattern. That's pretty much it. Good luck! Symbols: n1 = # n2=\ n3 = / n4=_ Implement the following functions: int getNum(); /*accepts input from the user."/ void display (int n, int n2, int n3, int n4); /*displays the given pattern/
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:1. DIY Pattern (from
codeChum, modified)
by Catherine Arellano
Step right up and create the pattern! Whoever gets
all patterns right will be crowned the new King of
Patterns and gets to brag about it to their friends.
Here are the instructions: you will be given 4
numbers; each number corresponds to the amount
of times a symbol is repeated in the pattern. That's
pretty much it. Good luck!
Symbols:
n1 = #
n2 = \
n3 = /
n4=_
Implement the following functions:
int getNum();
/*accepts input from the user.*/
void display (int n, int n2, int n3, int n4);
/*displays the given pattern*/
main.c
1
2
3
4
diy.h X
int getNum();
/*accepts input from the user.*/
5
void display (int n1, int n2, int n3, int n4);
6 /*displays the given pattern*/
< > + C
Custom Input
CE Run Tests
O Test Case 1
Input
Your
Output
Output
Expected
Output
3
2
1
4
No Output
O Test Case 2
Test Cases
Ex
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