Question in image. i need help with q 2 BackgroundSiphoning, the process of using a tube to carry a liquidover a barrier and to a lower location, can be described wellbythe mechanical energy equation. In this assignment youwill analyse siphoning behaviour theoretically, and thenwill carry out an experiment using a plastic bottle andlength of tubing provided to you.The plastic bottle has a nominal volume of one litre.However, two marks have been placed on the side of thebottle such that the corresponding volume between the twoAZmarks is approximately AV = 650 cm3. The plastic tubinggiven to you has an inside diameter of D = 2 mm and alength of L = 100 cm. In the picture to the right, Az is thevariable distance between the liquid level in the bottle andthe tube outlet level.The diameter of the tube is small enough that the flow inside will be laminar, anorderly state of flow in which a = 2 in the mechanical energy equation. Furthermore,the friction (wterm canexpressed as wf = kFLuavgwhere k = 9.5s-1 is a friction constant for room-temperature laminar flow of water inthis particular tubing. L is end-to-end length of tube and yovg is the average velocity inthe tube. You may take the water density to be 999kg/m3.AnalysisForthis experiment the analysis will be performed first.1. Calculate the volumetric flow rate of the siphon (cm3/s), assuming that L=100cm,Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get thevolumetric flow rate, you must first calculate ygvg:2. Predict the volumetric flow rate of the siphon (cm3/s), assuming that L = 100cm,Az = 80cm, and that there is friction in the tube (wi given by equation above).3. Repeat the flow rate calculation from number 2 with the following change: assume ahalf-length of tubing is used, with L = 50 cm and Az = 33 cm1

Siphon: It is a pipe or tube that is used to transfer a fluid in fluid mechanics. It can be to…

1. Calculate the volumetricflow rate of the siphon (cm³/s), assuming that L= 100cm, Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get the volumetric flow rate, you must first calculate ygva, 2. Predict the volumetric flow rate of the siphon (cm³/s), assuming that L = 100 cm, Az = 80cm, and that there is friction in the tube (Wgiven by equation above). 3. Repeatthe flow rate calculation from number 2 with the following change: assume a half-length of tubing is used, with L = 50 cm and Az = 33 cm

1. Calculate the volumetricflow rate of the siphon (cm³/s), assuming that L= 100cm, Az = 80 cm, and that there is no friction in the tube (w = 0). In order to get the volumetric flow rate, you must first calculate ygva, 2. Predict the volumetric flow rate of the siphon (cm³/s), assuming that L = 100 cm, Az = 80cm, and that there is friction in the tube (Wgiven by equation above). 3. Repeatthe flow rate calculation from number 2 with the following change: assume a half-length of tubing is used, with L = 50 cm and Az = 33 cm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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