1. A 9.0 m uniform beam is hinged to a vertical wall and held horizontally by a 5.0 m cable attached to the wall 4.0 m above the hinge, as shown below. The metal of the cable has test strength of 1.00 KN (kilo-Newton), which is the maximum tension magnitude T the cable can support. That means the cable will break if T is greater than this value. Let the mass m of the beam be 10.00 kg. (a) Will the cable break under the load of the beam mass given? If the answer is no, then what is the tension T? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR T. Remember. The magnitude of the weight is mg. (b) What is the largest beam mass m (corresponding to the test strength) the cable can support with the given configuration shown? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR THE MASS m. Remember. The magnitude of the weight is mg. Find the horizontal and vertical components of the force the hinge exerts on (d) the beam.
1. A 9.0 m uniform beam is hinged to a vertical wall and held horizontally by a 5.0 m cable attached to the wall 4.0 m above the hinge, as shown below. The metal of the cable has test strength of 1.00 KN (kilo-Newton), which is the maximum tension magnitude T the cable can support. That means the cable will break if T is greater than this value. Let the mass m of the beam be 10.00 kg. (a) Will the cable break under the load of the beam mass given? If the answer is no, then what is the tension T? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR T. Remember. The magnitude of the weight is mg. (b) What is the largest beam mass m (corresponding to the test strength) the cable can support with the given configuration shown? Hint: Set the next torques to be zero about the axis at the intersection between the beam and the wall at the hinge. THE TORQUES THAT ADD TO ZERO ARE DUE TO THE TENSION AND THE DOWNWARD WEIGHT OF THE BEAM. THEN SOLVE FOR THE MASS m. Remember. The magnitude of the weight is mg. Find the horizontal and vertical components of the force the hinge exerts on (d) the beam.
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter12: Static Equilibrium And Elasticity
Section: Chapter Questions
Problem 38P: A uniform horizontal strut weighs 400.0 N. One end of the strut is attached to a hinged support the...
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