1. A 0.5854-kg hammer is moving horizontally at 7.369 m/s when it strikes a nail and comes to rest after driving the nail 2.885 cm into a board. A small cartoon might be helpful. (a) Calculate the duration of the impact. Hint: Assume that the force of the hammer and, therefore, the acceleration of the nail is constant. You may use the equations or motion of an object, in this case the hammer, with constant acceleration. What quantities are known? Which equation is suitable to solve for the time it takes the nail to drive into the board. At= (b) What was the average force exerted on the nail? N Fnet = S

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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1. A 0.5854-kg hammer is moving horizontally at 7.369 m/s when it strikes a nail and comes to rest
after driving the nail 2.885 cm into a board. A small cartoon might be helpful.
(a) Calculate the duration of the impact.
%
O
5
Hint: Assume that the force of the hammer and, therefore, the acceleration of the nail is constant.
You may use the equations or motion of an object, in this case the hammer, with constant
acceleration. What quantities are known? Which equation is suitable to solve for the time it takes the
nail to drive into the board.
At=
(b) What was the average force exerted on the nail?
Fnet
N
T
G
=
3'
1640
6
Y
H
&
4-
7
B BN
S
hp
U
18
*
J
00
8
M
|
S
K
<
f10
O
L
?
P
>
52°F
→
{
[
?
insert
1
}
1
11:20 A
10/28/20
prt sc
backs
←
paus
Transcribed Image Text:1. A 0.5854-kg hammer is moving horizontally at 7.369 m/s when it strikes a nail and comes to rest after driving the nail 2.885 cm into a board. A small cartoon might be helpful. (a) Calculate the duration of the impact. % O 5 Hint: Assume that the force of the hammer and, therefore, the acceleration of the nail is constant. You may use the equations or motion of an object, in this case the hammer, with constant acceleration. What quantities are known? Which equation is suitable to solve for the time it takes the nail to drive into the board. At= (b) What was the average force exerted on the nail? Fnet N T G = 3' 1640 6 Y H & 4- 7 B BN S hp U 18 * J 00 8 M | S K < f10 O L ? P > 52°F → { [ ? insert 1 } 1 11:20 A 10/28/20 prt sc backs ← paus
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