1-chloro-3-methylcyclopentane was reacting with 4. Optical active compound potassium t-butoxide in t-butanol. Two alkene products were obtained. The main product was optically active, and the secondary product was not optically active. What are the two products? single enantiomer OK* OH

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter9: Nucleophilic Substitution And Β-elimination
Section9.5: Β-elimination
Problem 9.6P: Predict the -elimination product(s) formed when each chloroalkane is treated with sodium ethoxide in...
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Optical active compound 1-chloro-3-methylcyclopentane was reacting with
potassium t-butoxide in t-butanol. Two alkene products were obtained. The
main product was optically active, and the secondary product was not
optically active. What are the two products?

1-chloro-3-methylcyclopentane
was reacting with
4. Optical active compound
potassium t-butoxide in t-butanol. Two alkene products were obtained. The
main product was optically active, and the secondary product was not
optically active. What are the two products?
CI
Six
single enantiomer
OK*
OH
Transcribed Image Text:1-chloro-3-methylcyclopentane was reacting with 4. Optical active compound potassium t-butoxide in t-butanol. Two alkene products were obtained. The main product was optically active, and the secondary product was not optically active. What are the two products? CI Six single enantiomer OK* OH
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