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Pt1420 Unit 6 Research Paper

Satisfactory Essays

So we start of with x^2-4x+y^2+8y=-4 you would then take 1/2 of -4 and square it, then take 1/2 of 8 and square it. You would then get x^2-4x+4-4+(y^2+8y+16-16=-4. After all of these steps you would factor the square, x-2^2-4+y+42-16=-4, x-2^2+y+4^2-20=-4. Then you would add 20 to both sides, x-)^2+y+4^2=16 x-2^2+y+4^2=4^2. In this form, x-h^2+y-k^2=r^2 center is h,k, the radius is r in this equation, the center is (2,-4). With all of this being said, the radius of the circle would be 4.

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