University of Phoenix Material
Week 4 Practice Worksheet
Prepare a written response to the following questions.
Chapters 9 &11
1. Two boats, the Prada (Italy) and the Oracle (USA), are competing for a spot in the upcoming America’s Cup race. They race over a part of the course several times. The sample times in minutes for the Prada were: 12.9, 12.5, 11.0, 13.3, 11.2, 11.4, 11.6, 12.3, 14.2, and 11.3. The sample times in minutes for the Oracle were: 14.1, 14.1, 14.2, 17.4, 15.8, 16.7, 16.1, 13.3, 13.4, 13.6, 10.8, and 19.0. For data analysis, the appropriate test is the t-Test: Two-Sample Assuming Unequal Variances.
The next table shows the results of this independent t-test. At the .05 significance level, can we conclude
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For Data Analysis, a t-Test: Two-Sample Assuming Unequal Variances was used.
At the .01 significance level is there a difference in the mean amount purchased on an impulse at the two stores? Explain these results to a person who knows about the t test for a single sample but is unfamiliar with the t test for independent means.
Hypothesis Test: Independent Groups (t-test, unequal variance) Peach Street Plum Street 15.8680 18.2921 mean 2.3306 2.5527 std. dev. 10 14 n 20 df -2.42414 difference (Peach Street - Plum Street) 1.00431 standard error of difference 0 hypothesized difference -2.41 t .0255 p-value (two-tailed) -5.28173 confidence interval 99.% lower 0.43345 confidence interval 99.% upper 2.85759 margin of error
3. Fry Brothers heating and Air Conditioning, Inc. employs Larry Clark and George Murnen to make service calls to repair furnaces and air conditioning units in homes. Tom Fry, the owner, would like to know whether there is a difference in the mean number of service calls they make per day. Assume the population standard deviation for Larry Clark is 1.05 calls per day and 1.23 calls per day for George Murnen. A random sample of 40 days last year showed that Larry Clark made an average of
The type of t-Test is level to the variance, the independent t-test two groups are discrete and is exclusive due to the number (15) in each group, and the variance of the two groups is equal.
Explain, using the appropriate p-value. With a 0.0128 p-value this means the exact level of significance for a T-Ratio of 2.63 is 1 % and the level of confidence is 99%. Stating b is statistically significant.
Table 3 contains the one sample t-test results of during the season and after the season grade point averages. A one sample t-test was run to determine whether there was a statistically significant difference
For this data set, the student t-test is best to be used in testing the hypothesis. Here, two tailed-sample tests would be used at a level of significance of 5%. This will help us to pick an alpha at 0.25 in each tail to test the direction, which the test statistic is significant(LAWRANCE, 1987, p. 280). The relationship in both directions is significantly tested by our hypothesis which will compare the mean of the given sample population to the given value x obtained by the t-test. We shall then use the obtained p-value to make a decision whether to accept or reject our null hypothesis.
The pvalue for t-test is 0.3520178 for a two tail test. Group 1 has N of 8, and Group 2 has N of 10. Degrees of Freedom for Group 1 and 2 is 16 . The confidence level for both group 1 and 2 is 95% (0.05). Since the absoluate value level 0.89893315, therefore, we are going to Fail to reject the null hypothesis because the pvalue was greater than the confidence level, and there was a difference between both groups.
auto insurance offered by two leading companies. He selects a sample of 15 families, some with only a single insured driver, others with several teenage drivers, and pays each family a stipend to contact the two companies and ask for a price quote. To make the data comparable, certain features, such as the deductible amount and limits of liability, are standardized. The sample information is reported below. At the .10 significance level, can we conclude that there is a difference in the amounts quoted?
He selects a sample of 15 families, some with only a single insured driver, others with several teenage drivers, and pays each family a stipend to contact the two companies and ask for a price quote. To make the data comparable, certain features, such as the deductible amount and limits of liability, are standardized. The sample information is reported below. At the .10 significance level, can we conclude that there is a difference in the amounts quoted?
Test Statistic, t: -2.6515, Critical t: ±2.146376, P-Value: 0.0191, Degrees of freedom: 14, 95% Confidence interval: -2.895174 < µ1-µ2 < -0.3048258
The goal of this experiment is to collect measureable data from two different populations and conclude whether there is a difference between the means of the two populations. The two populations chosen for this study were male and female students who attend Montclair State University. The variable tested for this study was the number of songs from a random sample of males and females. To collect the random samples from the two populations, I approached various students on campus and asking them for the number of songs on their phone or listening device. I approached students in numerous places on campus such as the Student Center, the Sprague Library, University Hall, Car Parc
The purpose of the assignment is to review basic hypothesis testing and regression techniques. There is an appendix in your textbook, Appendix C: Using Excel to Conduct Analysis, which may help you with running regressions in Microsoft Excel. You may also wish to use a basic statistics text for guidance if needed. I have also provided you with a table with the t distribution.
In Problem 1, a two-tailed (non-directional) test was conducted since the test is to determine whether the mean is different for the GPA averages between men and women within the MBA program at Whatsamatta U (Mirabella, 2011). In hypothesis testing, the p-value is the likelihood of detecting a sample marker as excessive as the test value (Hypothesis Test, n.d.). Therefore, the p-value of
Learning Team A decided that the t test statistic must be used because the population variance in unknown. If we assume that the population variances are equal, we can take
(The Table value for significance at 0.05 level with df 2 and 57 and 2 and 56 are 3.14 and 3.15 respectively)
At 1 percent significance level, and 21-2=19 degrees of freedom, the critical values are are given as +/- 2.860. Since the t-ratio for price is -3.5869, which is greater than
The t-test can be used to test whether two groups are different. The independent t-test is used when there are two experimental conditions (e.g. male and female or public and private banks) and different participates have been used in each condition (e.g. SECI and innovation processes). Independent t-test table yielded by PASW normally mentions two rows for the test statistics: one row is labelled Equal variance assumed, while the other is labelled Equal variances not assumed. Which row is considered is based on the significant of Levene's test for Equality of Variances. Therefore, if the Levene’s test is significant, the Equal variances not assumed row will be used for the t-test. The significant of this difference is based on the significant of the t-test. That is, if this test is significant, it could be included that the difference between the means of these