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Nt1320 Unit 2 Agression Analysis Paper

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State your results: the mean, median, mode, range, variance, and standard deviation Based on the given sample of student test scores of 50, 60, 74, 83, 83, 90, 90, 92, and 95 after rearranging them from least to greatest. As the mean is based on the average of sum, the average of this sample is 79.67 or 80. The mode refers to numbers that appear the most in a sequence and in this case 83 and 90 both appear twice. Range calculates the difference between the largest and smallest number, which are 95 and 50 which have a difference of 45. The variance is the difference between the sum of squares divided by the sample size, which is the number in the sample minus one (Hansen & Myers, 2012), meaning it takes each number of the set and subtracts …show more content…

The best method to solve for the mean, medium, mode, range, variance, and standards deviation, in this case is by hand and not on SSPS. For a novice, they would spend more time figuring how to set the parameters and spend roughly the same amount of time on the analyzation that they would when using the software. Although, a moderate user of the SSPS software would solve this problem rather quickly. Though, it is recommended to use SSPS when analyzing a large sample size.
Conduct a one-sample t-test and interpret the results (use a population mean of 70). One-sample t-test are used in the parametric test which analyzes the means of populations. The t-test for independent groups are statistics that relates difference between treatment means to the amount of variability expected between any two samples of data within the same population (Hansen & Myers, 2012). Critical values are used in significant testing provide a range of t distribution that is used in whether a null hypothesis is rejected. Based on the data below as the level of significance is at .05, thus the critical values would fall under ±1.860 and the t value for this is 1.871 would suggest for the null to be rejected as it is greater than the critical value (Privitera, 2015, p. 267). Based on the population mean of 70 there was a mean difference of

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