State your results: the mean, median, mode, range, variance, and standard deviation Based on the given sample of student test scores of 50, 60, 74, 83, 83, 90, 90, 92, and 95 after rearranging them from least to greatest. As the mean is based on the average of sum, the average of this sample is 79.67 or 80. The mode refers to numbers that appear the most in a sequence and in this case 83 and 90 both appear twice. Range calculates the difference between the largest and smallest number, which are 95 and 50 which have a difference of 45. The variance is the difference between the sum of squares divided by the sample size, which is the number in the sample minus one (Hansen & Myers, 2012), meaning it takes each number of the set and subtracts …show more content…
The best method to solve for the mean, medium, mode, range, variance, and standards deviation, in this case is by hand and not on SSPS. For a novice, they would spend more time figuring how to set the parameters and spend roughly the same amount of time on the analyzation that they would when using the software. Although, a moderate user of the SSPS software would solve this problem rather quickly. Though, it is recommended to use SSPS when analyzing a large sample size.
Conduct a one-sample t-test and interpret the results (use a population mean of 70). One-sample t-test are used in the parametric test which analyzes the means of populations. The t-test for independent groups are statistics that relates difference between treatment means to the amount of variability expected between any two samples of data within the same population (Hansen & Myers, 2012). Critical values are used in significant testing provide a range of t distribution that is used in whether a null hypothesis is rejected. Based on the data below as the level of significance is at .05, thus the critical values would fall under ±1.860 and the t value for this is 1.871 would suggest for the null to be rejected as it is greater than the critical value (Privitera, 2015, p. 267). Based on the population mean of 70 there was a mean difference of
1. By hand, compute the mean, median, and mode for the following set of 40 reading scores:
1. For the following scores, find the mean, median, and the mode. Which would be the most appropriate measure for this data set?
I enjoyed reading your post. It seems that you have some familiarity with working with SPSS21 which is awesome because that will give you a good head start. When it comes to learning something new especially in an area that is outside of your comfort zone it is hard not to experience an elevated level of anxiety. You pointed out some great key facts that there are different branches of statistics which analyzes two total different perspectives. Working in healthcare I guess this information would be deemed necessary in helping to understand different areas of an organization dealing with issues such as market opportunities helping forecast potential issues in the
Where, m ̅_(H,i) is the remaining probability mass that is not yet assigned to individual grades caused by the relative importance of the attribute i (denoted by e_i). It will be one if the weight of e_i is zero or ω_i=0 ; and will be zero if e_i dominates the assessment or ω_i=1. m ̃_(H,i) is the remaining probability mass unassigned to individual grades caused by the incompleteness of the assessment. m ̃_(H,i) will be zero if assessment is complete, or ∑_(n=1)^N▒β_(n,i) =1; otherwise, m ̃_(H,i) will be positive. m_(n,I(i)) and m_(H,I(i)) can be generated by combining the basic probability masses m_(n,j) and m_(H,j) for all n=1,…,N,j=1,…,i. Given the previous definitions and discussions, the ER algorithm can be summarized as
1. By hand (without using SPSS), compute the mean, median, and mode for the following set of 40 reading scores:
Range (X) = Highest Value of Weight – Lowest value of weight = 8.2-7.4 = 0.8
In order to test the effectiveness of IGA and GA when solving the timetabling problem, a comparison with the PSO algorithm was performed to investigate trends of performance. All coding was written in MATLAB code and the test case focused on the three above algorithms. All tests were executed on a 3.30 Ghz Intel core i5 processor with 16 GB of ram. The convergence graphs for IGA, GA, and PSO below shows progress until a valid solution for each of the algorithms were discovered. Each of the algorithms simulated 1,000 generations. The graph in Figure 10 - 14 provides a comparison of the proposed algorithm with the conventional population operator based algorithm.
As shown in response table gives that demand time is more influencing factor than other factors. Than velocity of AGVs affects the system utilization and distance preference is very less influencing factor for system utilization.
In this case, we are dealing with a between subject experiment where one of the groups is tested in condition A while another group is tested with condition B. We can see from the set of data that we got outliers. To get rid of the outliers, we can calculate the interquartile mean by find the interquartile range first. This method can help to trim the outliers in the data.
Calculate the mean, the median, and the mode for each of the following data sets:
The pvalue for t-test is 0.3520178 for a two tail test. Group 1 has N of 8, and Group 2 has N of 10. Degrees of Freedom for Group 1 and 2 is 16 . The confidence level for both group 1 and 2 is 95% (0.05). Since the absoluate value level 0.89893315, therefore, we are going to Fail to reject the null hypothesis because the pvalue was greater than the confidence level, and there was a difference between both groups.
With 14 degree of freedom and .10 significance level, the critical t values are -1.761 and 1.761.
Mean, median and mode are representative values and they are important factors in statistics. As seen in
3.3 – Calculate the mean, median, and mode of each of the following population of numbers.
Mean is less than 2.5 which tells us that respondent are more inclined towards survivors which are low resources in VALS framework and standard deviation is slightly greater than 1 which indicates that the respondent are spread out over a wider range of values(mean).