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Dehydration Of Sulfuric Acid And Phosphoric Acid

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Dehydration of 2-methylcyclohexanol Authors: Johnny Presley Abstract: Dehydration of 2-methylcyclohexanol to 3-methylcyclohexene is simple distillation where dehydration was used to prepare the final product. The results of the experiment showed that the 3-methylcyclohexene was formed via an E1 reaction from 2-methylcyclohexanol with a 1:1 ratio of sulfuric acid and phosphoric acid. However, some H2O was left over, which was seen when we look at the IR and see a small water peak. This could be due to the fact that not enough sodium sulfate was added and not for long enough. These results were confirmed by the quality tests that showed that a precipitate formed when KMnO4 was added to the solution and in the IR spectroscopy peaks showed peaks at 3022.62cm-1 which matches an alkene, further showing that the formation of 3-methylcyclohexene was successful with a percent yield of 56.46%. Introduction: The major reaction that happened was an E1 reaction (otherwise known as a unimolecular elimination reaction). In this reaction the removal of an HX substituent group results in the formation of a double bond via beta hydrogen elimination4. In an E1 reaction the deprotonation of hydrogen in the beta position occurs and from here a carbocation is formed, which results in the formation of an alkene product. This happens when the OH group on the 2-methylcyclohexanol is hydrated by H2SO4, which allows the OH to become an H2O. Since H20 is a better leaving group now it will

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