CHEE 4704 - Problem Set 2a - Solutions
.pdf
keyboard_arrow_up
School
Dalhousie University *
*We aren’t endorsed by this school
Course
4704
Subject
Chemistry
Date
Jan 9, 2024
Type
Pages
10
Uploaded by yessssirsad on coursehero.com
CHEE 4704: Separation Processes II
Fall 2023 Problem Set 2a Solutions: Liquid-Liquid Extraction Page 1 of 10 Problem Set 2a Solutions Liquid-Liquid Extraction Problem 1: Extraction with Immiscible Solvents A water solution of 100 kg/h containing 1.0 wt% nicotine in water is extracted with a kerosene stream containing 0.05 wt% nicotine in a countercurrent stage tower. The exit water is to contain only 0.1 wt% of the original nicotine, that is, 90% is removed. Equilibrium data is provided in the table below. a)
Determine the minimum solvent kerosene flow rate to perform the desired extraction. (
103.17 kg/h
) b)
Using 1.5 times the minimum solvent flow rate, determine graphically the number of theoretical stages required. (
6.01 stages
) c)
Determine analytically the number of theoretical stages required. (
6.8 stages
) Solution a)
An appropriate block flow diagram for the process: The nicotine recovery can be used to calculate the concentration in the exiting water stream: 𝑅?
𝑁
= (1 − 0.9)?
0
𝑅 → ?
𝑁
= 0.001
The slope of the equilibrium curve can be found by fitting a linear trendline to the equilibrium data. Note that the equilibrium curve is not a perfectly straight line; however, we can approximate the slope using a linear trendline.
CHEE 4704: Separation Processes II
Fall 2023 Problem Set 2a Solutions: Liquid-Liquid Extraction Page 2 of 10 The minimum solvent flow rate is, 𝐸
?𝑖?
=
𝑅
??
0
− ?
𝑁+1
?
0
− ?
𝑁
=
100 kg/h
[(0.9224)(0.01) − 0.0005]
(0.001 − 0.001)
= 103.17 kg/h
Alternatively, the minimum solvent flow rate can be found by varying 𝐸
?𝑖?
until the operating line pinches the equilibrium line. Using this method 𝐸
?𝑖?
= 99 kg/h
. Either method is acceptable. b) The actual solvent flow rate is, 𝐸
′
= 1.5𝐸
min
′
= 1.5(
103.17 kg/h
) = 154.75 kg/h
The concentration in the exiting kerosene stream can be determined using a nicotine mass balance on the overall system: 𝑅?
0
+ 𝐸?
𝑁+1
= 𝑅?
𝑁
+ 𝐸?
1
?
1
=
𝑅?
0
+ 𝐸?
𝑁+1
− 𝑅?
𝑁
𝐸
=
(100
?𝑔
ℎ
) (0.01) + (
103.17
kg
h
)
(0.0005)
− 𝑅?
𝑁
𝐸
?
1
=
(100 kg/h)(0.01) + (154.75 kg/h)
(0.0005)
− (100 kg/h)(0.001)
(154.75 kg/h)
= 0.005816
The operating line can be plotted between the following points: (?
𝑁
, ?
𝑁+1
) → (0.001, 0.0005)
(?
0
, ?
1
) → (0.01, 0.005816)
CHEE 4704: Separation Processes II
Fall 2023 Problem Set 2a Solutions: Liquid-Liquid Extraction Page 3 of 10 The number of stages can now be stepped off. The stages can be stepped off using the following procedure: 1)
Start at (?
𝑁
, ?
𝑁+1
) → (0.001, 0.0005)
. 2)
Set ? = ?
???
and calculate ? = [polynomial
fit
to
equilibrium
curve]
. 3)
Set ? = ?
???
and calculate ?
from the operating line: ? =
(𝑦−𝑏)
𝑠????
. 4)
Repeat 2 to 3 until ? ≥ ?
1
. The McCabe-Thiele plot shows that the required number of equilibrium stages is approximately 6.01. c) The equilibrium line can be divided into two separate lines with a linear slope:
CHEE 4704: Separation Processes II
Fall 2023 Problem Set 2a Solutions: Liquid-Liquid Extraction Page 4 of 10 The slope at the bottom of the equilibrium line: ?
𝑁
= 0.79626
The slope at the top of the equilibrium line: ?
1
= 0.9178
The flow rate of raffinate at the bottom of the operating line (or equilibrium line): 𝑅
𝑁
=
𝑅(1 − ?
0
)
1 − ?
𝑁
=
(100 kg/h)(1 − 0.01)
1 − 0.001
= 99.1 kg/h
The flow rate of the solvent at the bottom of the operating line (or equilibrium line): 𝐸 = 154.75 kg/h
The flow rate of raffinate at the top of the operating line (or equilibrium line) is just the feed raffinate flow rate. 𝑅 = 100 kg/h
The flow rate of the solvent at the top of the operating line (or equilibrium line): 𝐸
1
=
𝐸(1 − ?
𝑁+1
)
1 − ?
1
=
(154.75 kg/h)(1 − 0)
1 − 0.0045
= 155.58 kg/h
The extraction factor at the bottom of the equilibrium line: 𝐴
𝑁
=
𝑅
𝑁
?
𝑁
𝐸
=
99.1 kg/h
(0.79626)(154.75 kg/h)
= 0.8042
The extraction factor at the top of the equilibrium line: 𝐴
1
=
𝑅
?
1
𝐸
1
=
100 kg/h
(0.9178)(155.58 kg/h)
= 0.7003
The extraction factor:
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
4.21. A dilute aqueous solution of H SO, (Solution A) is to be mixed with a solution containing 90.0 wt%
H2SO, (Solution B) to produce a 75.0 wt% solution (Solution C).
Solution A
Flowmeter A
Analyzer
Solution C
75% H,S0,
Solution B
90% H,SO.
Flowmeter B
MIXER
The flow rate and concentration of Solution A change periodically, so that it is necessary to adjust
the flow rate of Solution B to keep the product H,SO, concentration constant.
Flowmeters A and B have linear calibration plots of mass flow rate (in) versus meter reading
(R), which pass through the following points:
Flowmeter A: mA
150 lb/h, RA
25
%3D
%3D
500 lbm/h, RA
70
%3D
%3D
Flowmeter B: mp = 200 lbm/h, Ry = 20
800 lbm/h, Rg 60
%3D
The analyzer calibration is a straight line on a semilog plot of %H;SO4(x) on a logarithmic scale
versus meter reading (R,) on a linear scale. The line passes through the points (x
and (x
(a) Calculate the flow rate of Solution B needed to process 300 lb/h of 55% H,SO, (Solution A),
and the…
arrow_forward
1000 kg/hr of a mixture of benzene (B) and Toluene (T)
containing 50% benzene by mass is separated by
distillation into two fractions. The mass flow rate of
benzene in the top stream is 450 kg B/hr and that of
Toluene at the bottom is 475 kg T/h. the operation is
at steady. What is the mass fraction of benzene at the
bottom stream?
О а. 0.015
O b. 0.095
О с. 0.23
O d. 0.132
arrow_forward
For the purpose of determination of
agricultural pesticides in river water,
3.2 liters of river water were taken and
extracted with 125ml of CCI4 solvent
using a separating funnel. After
shaking and reaching the state of
equilibrium, if you know that the value
of the distribution coefficient (KD) is
equal to 20, the weight ratio of the
pesticides in the boiling layer to the
lower layer in the separating funnel?
arrow_forward
Ex7;
An aqueous solution of sodium hydroxide contains 20.0% NaOH by mass. It is desired to
produce an 8.0% NaOH solution by diluting a stream of the 20% solution with a stream of
pure water. Calculate the ratios (liters H20/kg feed solution) and (kg product solution/kg
feed solution).
F =? kg
= 0.2
XNaOH
P =? kg
XH,0
= 0.8
F2 =? kg
F2
= 0.08 kg Na0H/kg
xH,0 = 0.92 kg H20/kg
%3D
1
arrow_forward
0 A too kmal/h stream that is 97 msle % Carbon tetrachlorice Ccc4)
and 3 % Carbon disullide ccs) is to be recovered Prom the bottom
of a distillation column. The feed to the column is 16 mole % CS, and
84 % Cc4, and 2 % of the cc4 enterirg the column is contained
in the overhead stream leaving H top of 'the column-
O a flow charf of the pocess and do the degree-of-
Drae and label
freedom analysis-
Clculate the mass and mle fracklons of Ccl4 in the overhend stranm,
and determine He malar Piow rates of cc4 & CS, in the overhend and
feel streams
arrow_forward
In liquid-liquid extraction process, the fraction of solute remaining in phase
1 after n extractions is given by the formula below:
q"
=
V
1
V + KV
A solute is transfered from water (100 mL) to ether (15 mL). If the
distribution coefficient between water and ether is 0.5, and three
extractions are performed, what fraction of the solute remains in the
aqueous phase after these extractions?
a. 0.012
b. 0.752
c. 0.930
12
d. 0.230
arrow_forward
BC Broward Col x
O Onelogin
xe Expt. 6 pre-l xA "Expt. 7 Quiz X
G .What is an x
b ziprecruiter x
O 12.628+ Par X
E Login
x +
O File | C/Users/nerbs/Downloads/Expt.%207%20Quiz,%20Part%201.pdf
10
2) If absorptivity (the constant of how much light of a given wavelength the sample absorbs) and path
length (how much solution there is for light to pass through) are the same, which is true for a Beer's Law
solution?
a) its concentration and absorbance are proportional
b) its concentration and rate are proportional
c) its absorbance and rate are proportional
d) the solution is an alcoholic beverage
arrow_forward
Gypsum (CaSO4) is a common percipitant in water desalination.
CaSO4 <=> Ca2+ + SO42- where Ksp=10-4.6.
Assuming that: [Ca2+]=2x10-2 M; [SO42-]=2x10-3M:
a) Find Qsp or IAP for the given water
b) Find the solubility index (SI) and determine whether CaSO4 is under, super, or at saturation in water.
Feel free to make any assumptions you wish, as long as they're stated.
arrow_forward
令 。
B/s
因 1:Y9
404
2_543841247..
Use of the Normal Law
Normality (N) = Wt /Eq.wt 1000/V(ml)
Wt (gm) =Weight of sodium carbonate
V (ml) = solution volume
N= Normality
Discussion:
1. What is the equivalent weight of the vehicle?
primary standard?
2. Why is sodium carbonate
3- Attend naciN 3.3 solution in a 253 mi volume bottle.
4- Calculate the caliber of sodium carbonate if the weight of
sodium carbonate gm 2 and the size of the bottle volume is
100ml
Results Sheet
Name:
Group:
Date:
Signature
1-Calculations:
2-Aim of experiment:
3-Theoretical results
M(Na2Co3).. ..
Weight required=
4-Observations:
个
arrow_forward
A liquid mixture containing 40.0% benzene (B)
and 60% toluene (T) by mass to the distillation
column. The upper product stream contains 90
mol% B, and the lower product stream contains
6% of the benzene fed into the column
(meaning that 94% of the benzene is left with
the upper product). The volumetric flow rate of
the feed is 2500 1/ hr and the specific gravity of
.the feed mixture is 0.870
A- Rate of mass accumulation B- Component
balance equation . The accumulation terms (d/
dt), can also be diminished to zero by assuming
steady state
arrow_forward
How many mL of a 12.5 M solution are needed to make 100 mL of a 1.30 M
solution?
Your Answer:
Answar
units
arrow_forward
(17 (17
/courses/159861/files?preview=69941104
G Gmail
Frage b Ac (PISU Fil
الولايات المتحدة الفن @
Science Problem Set 2.pdf
W-
#
2 r 3
S»>>
F2
Dissolved substances
Az+
H*
Solid substances
Az
Az₂O
Liquid substances
H₂O
E
(a) 0.991 V
Why You Don't Ne...
80
F3
$
DS
Page of 2
Arizonium (Az) is a newly discovered element. Below is a Table listing the chemical potentials
at 300 K of the A+ cation and the Az₂O oxide.
A t
4
(a) 5.5
E
R
6. Determine the standard potential (Az* = 1M) for the reaction: Az* +e™ = Az
(a) 0.400 V.
(b) 0.500 V (c) 0.700 V
(d) 0.800 V
7. Determine the standard potential for the reaction: Az₂O + 2H+ + 2e = 2Az +H₂O
(b) 0.701 V (c) 0.698 V
(d) 1.203 V
F
000
000
8. Calculate the equilibrium constant, K, for the chemical reaction:2Az* + H₂O=Az₂O + 2H+
(a) 10-11.3 (b) 10-10.1
(c) 10-6.0
(d) 10-16.4
9. Determine the pH value at which the potential for the two reactions,
Azt +e=Az and Az₂O + 2H+ + 2e = 2Az +H₂O, intersect.
(b) 6.2
1¹9
ق
%
5
O
Juj M Int
μº chemical…
arrow_forward
Countercurrent Multistage Washing of Ore. A treated ore containing inert solid
sulfate is to be leached in a countercurrent multistage
gangue and copper
extractor using pure water to leach the CuSO4. The solid charge rate per hour
consists of 10000 kg of inert gangue (B), 1200 kg of CuSO, (solute A), and 400
kg of water (C). The exit wash solution is to contain 92 wt % water and 8 wt %
CuSO4. A total of 95% of the CuSO, in the inlet ore is to be recovered. The
underflow is constant at N
Calculate the number of stages required.
0.5 kg inert gangue solid/kg aqueous solution.
arrow_forward
What is the percentage of organic compound that is dissolved in soil pore water that has a porosity of 0.41 and the Kd = 563 L kg-1 ?
Report your answer in percentage and enter it is X.Xx10(-X) or X.Xx10(X)
arrow_forward
A 100 g soil containing 20% smectitie mineral matter was mixed with 150 mL solution
containing 0.10 M Pb. CEC of pure smectitie is 110 emol(+)/kg.
CEC of the soil (cmol(+)/kg) is:
arrow_forward
20 aspirin tablets labeled 80mg were dissolved in 100mL of 90% ethanol. A 10mL aliquot was taken and was used for assay. The analyte followed usual process and was treated with 50mL of 0.1000N NaH and was titrated with 35mL 0.1050N H2O4 until the solution achieved completion. Calculate the % content of the total aspirin capsules and the actual label claim
arrow_forward
The aqueous solution of acetic with a flow rate of 1000 kg/hr contains 30% acetic acid by mass and will be extracted in a countercurrent multistage process with pure isopropyl ether (IPE) to reduce the acetic acid concentration in the final raffinate phase (LN) to 2% by mass. a) Calculate the minimum solvent flow. b) Determine the theoretical number of steps required when using a solvent of 1.5 minimum solvent flow rate. c) Determine the number of theoretical steps using the McCabe-Thiele method. Chart. Acetic acid (A)-Water (B)-isopropyl ether (IPE) (C) LIQUID-Liquid Balances at 1 atm pressure and 293 K Water layer (%) Water (B) Isopropyl ether layer (%) Water (B) 0.6 Acetic acid (A) IPE (C) Acetic acid (A) IPE (C) 98.8 1.2 99.4 99.3 98.9 0.69 98.1 1.2 0.18 0.5 1.41 97.1 1.5 0.37 0.7 2.89 95.5 1.6 0.79 98.4 91.7 1.9 1.0 97.1 6.42 13.30 25.50 36.70 1.9 93.3 4.82 11.40 2.3 84.4 71.1 3.4 3.9 84.7 71.5 21.60 31.10 58.9 4.4 6.9 58.1 48.7 10.6 10.8 45.1 37.1 44.30 46.40 16.5 36.20 15.1…
arrow_forward
Kide solution.
Trial 1
Trial 2
Trial 3
,4
28.01 49,6041.10
28.0123,3O
to'9 Ĉ
2.89x1041,963.0
21.6
4,65 31717
rity of NAQH solution:
arrow_forward
A feed mixture containing 50 wt% n-heptane and 50 wt% methyl cyclohexane
(MCH) is to be separated by liquid-liquid extraction into one product containing
92.5 wt% methylcyclohexane and another containing 7.5 wt% methylcyclo-
hexane. Aniline will be used as the solvent.
(a) What is the minimum number of theoretical stages necessary to effect this
separation?
(b) What is the minimum extract reflux ratio?
(c) If the reflux ratio is 7.0, how many theoretical contacts will be required?
Liquid-liquid equilibrium data for the system n-heptane-methyl
cyclohexane-aniline at 25°C and at 1 atm (101 kPa)
Hydrocarbon Layer
Solvent Layer
Weight percent
MCH, solvent-
free basis
Pounds aniline/
pound solvent-
free mixture
Pounds aniline/
Weight percent
MCH, solvent-
free basis
pound solvent-
free mixture
0.0
0.0799
0.0
9.9
20.2
23.9
0.0836
0.087
0.0894
15.12
13.72
11.5
11.8
33.8
37.0
50.6
60.0
11.34
36.9
0.094
9.98
9.0
8.09
44.5
0.0952
0.0989
0.1062
50.5
67.3
66.0
76.7
84.3
88.8
6.83
74.6
79.7
82.1…
arrow_forward
Problem 4. A field site in Pensacola, FL, is contaminated with creosote compounds (a wood
preservative) in a nonaqueous phase liquid (NAPL) source. The mole fraction of phenol in the
creosote is 3.2 x 104 mole phenol/mole creosote. Assume that the NAPL source material in
extends vertically to the groundwater-unsaturated zone interface at the site. Estimate the partial
pressure of phenol (atm) in the soil gas immediately above the NAPL, assuming the system is at
equilibrium. Note: Phenol MW = 94 g/mol, vapor pressure = 0.00026 atm at 25°C.
arrow_forward
Mganga is doing a routine analysis in a copper plating factory. He is regularly making up solutions of verypure CuSO4.5H2O. He suspect that a batch of a reagent used to make up a stock solution of CuSO4.5H2Ois impure and it may contains some CuCl2. He asked you to determine the percentage impurity as follows:Dissolve1.500g of a mixture and make up to 1.00L mark.150mL of this solution was treated with 20.00mLof 0.100M AgNO3 to remove 98.6% of chloride as AgCl precipitate.
arrow_forward
Q3/ The solubility of sodium chloride NaCl in water at 290 K is 35.8 kg / 100 kg of water. Express
the solubility as the following:
1- Mass fraction and the mass percent of NaCl
2- Mole fraction and mole percent of NaCl
3- kmol of NaCl per 1000 kg of water
Note: molecular weight of NaCl = 135. 8, and water = 18.016
04/Aton ctroom of a dictillation col.umn uns docignod to romoue O504ofthe amount of componont
arrow_forward
Tirofiban (C22H36N2O5S MWt = 440.6) is present as tirofiban HCI monohydrate
(C22H36N2O5S.HCI.H₂O MWt=495.1) at 0.281 mg/mL in a concentrated solution.
A solution for infusion is prepared by extracting 50 mL from a 250 mL bag of 5% glucose solution
and adding 50 mL of concentrated solution.
Sofia who weighs weighs 87 kg requires a tirofiban dose of 0.1 mcg/kg/min for 12 to 24 hours.
What would the infusion rate be (mL/h)? (Answer to 1 decimal place.)
Answer: 125.28 X
arrow_forward
> EL
session.masteringchemistry.com
MasteringChemistry ROSTER-2019-SPRI-PULLM-CHEM-101
blackboard wsu Google Search
MasteringChemistry: HW 8
KHW 8
Applications for Dilution Calculations
K8 of8
Dilution as a procedure in analysis
We sometimes purposely dilute solutions if the analyte concentrations
wavelengths in the visible (and sometimes uitraviolet) range. Based on the dissolved solute's properties, we can quantify that solute's concentration
are too high to permit an accurate measurement. For example, a spectrophotometer can measure the amount of
light that passes through a sample solution for
If the solute's concentration is too high, a relatively small amount of incident light
having the wavelength that corresponds to the solute's absorption behavior will
less light is absorbed, and the detector in the spectrophotometer can generate more reliable data.
reach the dete
ctor, which results in an inaccurate measurement (consider the result if you blocked the light with an
opaque…
arrow_forward
POin Elevation
Aselution in preparnd by dissolving 15.60gof ordinary ger (sueroe, CHO, molecular weight-342 amu) in 15.00 gof water Calculante the boiling peier of the solution Sacose i
anovolatile nonelectrolyte
Solvent
TC)
THC)
rCkg/mal)
rChg/moll
Benzene, Cal
80.1
253
55
530
Camphor, Cato
204
176
37.7
Cyciohexane, CH
B0.88
2.79
6.50
202
Nitrobenzene,
Cll, NO,
2108
524
81
water, H0
100.0
0.00
Submit
Sho A h E
Try A
arrow_forward
(c)
The ore being placed on the heap has an average copper grade of 1.0% and the lixiviant
addition rate is 900 m3 /hr. 5% of the liquid is lost through evaporation and other loses
and the pregnant solution contains an average of 2.1 kg Cu/m³. The solvent extraction
stage recovers 90% of this copper, with the barren solution having additional acid and
water added to make up for the lost volume and consumed material before being added
back onto the heap. What is the average recovery of the copper from the heap leaching
assuming no losses in the SX/EW?
arrow_forward
1) 1500 kg mixture contains 15% acetone, 75% water and 10% Acetic acid by weight.
a) Calculate the total mole of mixture and molar fractions of each compound.
b) Calculate Average Molecular Weight of mixture.
c) 2 kmol more Acetic acid is added to the mixture. What would be the mass fractions of this
new mixture?
(MW: Acetone= 58 g/mol Water= 18 g/mol Acetic acid= 60 g/mol)
arrow_forward
You wish to undertake a 100 step countercurrent extraction of solutes A & B with distribution coefficients D= 1.5 & Da - 0.6. Suppose the volumes of mobile
and stationary are equal. If fractions 28-40 and 50-68 are each pooled find the % recovery and purity of each solute.
AA 79.8% recovery of 99.7% pure A
B: 82.0% recovery of 86.6% pure B
B. A: 72.7 % recovery of 97.0% pure A
B: 89.0 % recovery of 98.9 % pure B
OC.A: 82.6% recovery of 92.3% pure A
B: 82.9% recovery of 91.0% pure B
O D.A 92.6% recovery of 99.5% pure A
8: 67.0% recovery of 100 % pure B
arrow_forward
If 30.0 mL of water that is 0.0500 M in Q is to be extracted
with four 10.0-mL portions of an immiscible organic solvent,
what is the minimum distribution coefficient that allows
transfer of all but the following percentages of the solute to
the organic layer:
a 2.00 x 10-4
Distribution coefficient :
b2.00 x 10-3
Distribution coefficient
C2.00 x 10-²
Distribution coefficient
Submit Answer
=
Retry Entire Group
arrow_forward
12.10-3. Countercurrent Multistage Washing of Ore. A treated ore containing inert solid
gangue and copper sulfate is to be leached in a countercurrent multistage
extractor using pure water to leach the CUSO,. The solid charge rate per hour
consists of 10000 kg of inert gangue (B), 1200 kg of CuSO, (solute A), and 400
kg of water (C). The exit wash solution is to contain 92 wt % water and 8 wt %
CuSO4. A total of 95% of the CUSO, in the inlet ore is to be recovered. The
underflow is constant at N = 0.5 kg inert gangue solid/kg aqueous solution.
Calculate the number of stages required.
arrow_forward
Thank you
arrow_forward
A 3 m^3 drum contains a mixture at 101 KPa and 35 C of 60% Methane (CH4) and 40% oxygen (O2) on a volumetric basis. a. Determine the amount of oxygen that must be added at 35 C to change the volumetric analysis to 50% of each component.
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Related Questions
- 4.21. A dilute aqueous solution of H SO, (Solution A) is to be mixed with a solution containing 90.0 wt% H2SO, (Solution B) to produce a 75.0 wt% solution (Solution C). Solution A Flowmeter A Analyzer Solution C 75% H,S0, Solution B 90% H,SO. Flowmeter B MIXER The flow rate and concentration of Solution A change periodically, so that it is necessary to adjust the flow rate of Solution B to keep the product H,SO, concentration constant. Flowmeters A and B have linear calibration plots of mass flow rate (in) versus meter reading (R), which pass through the following points: Flowmeter A: mA 150 lb/h, RA 25 %3D %3D 500 lbm/h, RA 70 %3D %3D Flowmeter B: mp = 200 lbm/h, Ry = 20 800 lbm/h, Rg 60 %3D The analyzer calibration is a straight line on a semilog plot of %H;SO4(x) on a logarithmic scale versus meter reading (R,) on a linear scale. The line passes through the points (x and (x (a) Calculate the flow rate of Solution B needed to process 300 lb/h of 55% H,SO, (Solution A), and the…arrow_forward1000 kg/hr of a mixture of benzene (B) and Toluene (T) containing 50% benzene by mass is separated by distillation into two fractions. The mass flow rate of benzene in the top stream is 450 kg B/hr and that of Toluene at the bottom is 475 kg T/h. the operation is at steady. What is the mass fraction of benzene at the bottom stream? О а. 0.015 O b. 0.095 О с. 0.23 O d. 0.132arrow_forwardFor the purpose of determination of agricultural pesticides in river water, 3.2 liters of river water were taken and extracted with 125ml of CCI4 solvent using a separating funnel. After shaking and reaching the state of equilibrium, if you know that the value of the distribution coefficient (KD) is equal to 20, the weight ratio of the pesticides in the boiling layer to the lower layer in the separating funnel?arrow_forward
- Ex7; An aqueous solution of sodium hydroxide contains 20.0% NaOH by mass. It is desired to produce an 8.0% NaOH solution by diluting a stream of the 20% solution with a stream of pure water. Calculate the ratios (liters H20/kg feed solution) and (kg product solution/kg feed solution). F =? kg = 0.2 XNaOH P =? kg XH,0 = 0.8 F2 =? kg F2 = 0.08 kg Na0H/kg xH,0 = 0.92 kg H20/kg %3D 1arrow_forward0 A too kmal/h stream that is 97 msle % Carbon tetrachlorice Ccc4) and 3 % Carbon disullide ccs) is to be recovered Prom the bottom of a distillation column. The feed to the column is 16 mole % CS, and 84 % Cc4, and 2 % of the cc4 enterirg the column is contained in the overhead stream leaving H top of 'the column- O a flow charf of the pocess and do the degree-of- Drae and label freedom analysis- Clculate the mass and mle fracklons of Ccl4 in the overhend stranm, and determine He malar Piow rates of cc4 & CS, in the overhend and feel streamsarrow_forwardIn liquid-liquid extraction process, the fraction of solute remaining in phase 1 after n extractions is given by the formula below: q" = V 1 V + KV A solute is transfered from water (100 mL) to ether (15 mL). If the distribution coefficient between water and ether is 0.5, and three extractions are performed, what fraction of the solute remains in the aqueous phase after these extractions? a. 0.012 b. 0.752 c. 0.930 12 d. 0.230arrow_forward
- BC Broward Col x O Onelogin xe Expt. 6 pre-l xA "Expt. 7 Quiz X G .What is an x b ziprecruiter x O 12.628+ Par X E Login x + O File | C/Users/nerbs/Downloads/Expt.%207%20Quiz,%20Part%201.pdf 10 2) If absorptivity (the constant of how much light of a given wavelength the sample absorbs) and path length (how much solution there is for light to pass through) are the same, which is true for a Beer's Law solution? a) its concentration and absorbance are proportional b) its concentration and rate are proportional c) its absorbance and rate are proportional d) the solution is an alcoholic beveragearrow_forwardGypsum (CaSO4) is a common percipitant in water desalination. CaSO4 <=> Ca2+ + SO42- where Ksp=10-4.6. Assuming that: [Ca2+]=2x10-2 M; [SO42-]=2x10-3M: a) Find Qsp or IAP for the given water b) Find the solubility index (SI) and determine whether CaSO4 is under, super, or at saturation in water. Feel free to make any assumptions you wish, as long as they're stated.arrow_forward令 。 B/s 因 1:Y9 404 2_543841247.. Use of the Normal Law Normality (N) = Wt /Eq.wt 1000/V(ml) Wt (gm) =Weight of sodium carbonate V (ml) = solution volume N= Normality Discussion: 1. What is the equivalent weight of the vehicle? primary standard? 2. Why is sodium carbonate 3- Attend naciN 3.3 solution in a 253 mi volume bottle. 4- Calculate the caliber of sodium carbonate if the weight of sodium carbonate gm 2 and the size of the bottle volume is 100ml Results Sheet Name: Group: Date: Signature 1-Calculations: 2-Aim of experiment: 3-Theoretical results M(Na2Co3).. .. Weight required= 4-Observations: 个arrow_forward
- A liquid mixture containing 40.0% benzene (B) and 60% toluene (T) by mass to the distillation column. The upper product stream contains 90 mol% B, and the lower product stream contains 6% of the benzene fed into the column (meaning that 94% of the benzene is left with the upper product). The volumetric flow rate of the feed is 2500 1/ hr and the specific gravity of .the feed mixture is 0.870 A- Rate of mass accumulation B- Component balance equation . The accumulation terms (d/ dt), can also be diminished to zero by assuming steady statearrow_forwardHow many mL of a 12.5 M solution are needed to make 100 mL of a 1.30 M solution? Your Answer: Answar unitsarrow_forward(17 (17 /courses/159861/files?preview=69941104 G Gmail Frage b Ac (PISU Fil الولايات المتحدة الفن @ Science Problem Set 2.pdf W- # 2 r 3 S»>> F2 Dissolved substances Az+ H* Solid substances Az Az₂O Liquid substances H₂O E (a) 0.991 V Why You Don't Ne... 80 F3 $ DS Page of 2 Arizonium (Az) is a newly discovered element. Below is a Table listing the chemical potentials at 300 K of the A+ cation and the Az₂O oxide. A t 4 (a) 5.5 E R 6. Determine the standard potential (Az* = 1M) for the reaction: Az* +e™ = Az (a) 0.400 V. (b) 0.500 V (c) 0.700 V (d) 0.800 V 7. Determine the standard potential for the reaction: Az₂O + 2H+ + 2e = 2Az +H₂O (b) 0.701 V (c) 0.698 V (d) 1.203 V F 000 000 8. Calculate the equilibrium constant, K, for the chemical reaction:2Az* + H₂O=Az₂O + 2H+ (a) 10-11.3 (b) 10-10.1 (c) 10-6.0 (d) 10-16.4 9. Determine the pH value at which the potential for the two reactions, Azt +e=Az and Az₂O + 2H+ + 2e = 2Az +H₂O, intersect. (b) 6.2 1¹9 ق % 5 O Juj M Int μº chemical…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY