Exam 4 Take home portion Spring 23 Online TURN IN
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Name____________________________ Section________________________
Spring Exam 4 A&P 2 Take Home Portion
1.
Sex-linked genetically inherited traits (2pt)
a.
Can appear in both males and females b.
Are only found in males
c.
Are only found in females
d.
Result from traits passed by the mother
2.
Y-linked traits are inherited (2pt)
a.
Only by females b.
Only my males
c.
By both males and females
3.
Harmful x-linked traits are (2pt)
a.
Inherited only from mothers
b.
Most likely to show up in the phenotype of daughter c.
More numerous than Y-linked ones
4.
The sex of a child is determined by (2pt)
a.
The age of the parents
b.
Whether the father’s sperm contains an X or Y chromosome
c.
Whether the mother’s eggs contains an X or Y chromosome 5.
Why are men 16 times more likely to be color-blind than women? (2pt)
a.
To be color-blind, you must have a Y chromosome
b.
Color-blindness is caused by testosterone
c.
Color-blindness is caused by the same gene as baldness
d.
To be color-blind, all of your X chromosomes must have the gene
6.
In flies, eye color is a sex-linked trait. The allele for red eyes (X
R
) is dominant to the allele for
white eyes (X
r
). A male fly with red eyes X
R
Y and a carrier female X
R
X
r
are mated. What is the
probability that the female offspring will be carriers for white eyes? (use the punnet square below to help you answer the question.) (2pt) You answer must be in full sentence format for full credit. xw
xw
xw
xwxw
Xwxw
y
xwy
xwy
Answer
:
there is a 25% chance that the female offspring will be carriers for white eyes.
Name____________________________ Section________________________
Spring Exam 4 A&P 2 Take Home Portion
.
In humans the gene for normal blood clotting is dominant to the gene for hemophilia. X
N
= normal blood clotting, Xn = hemophilia. This gene is on the X chromosome.
7.
A woman heterozygous for the trait (X
N
X
n
) marries a man with hemophilia (X
n
Y). What is the probability of the couple having: (6pt) You answer must be in full sentence format for full credit.
a.
A normal (non-carrier) daughter? The probability of a normal non carrier daughter is 0%.
b.
A normal son? The probability of a normal son is 50%.
c.
A hemophilic Son? The probability of a normal son is 50%.
XN
Xn
Xn
XNXn
XnXn
Y
XNY
XnY
8.
Suppose that a normal woman marries a man with hemophilia. What is the probability of the couple having a: (4pt) You answer must be in full sentence format for full credit.
a.
A hemophilic son? the probability of the couple having a hemophilic son 25%.
b.
A hemophilic carrier daughter? the probability of the couple having a hemophilic carrier daughter 25%.
X
Xn
Xn
XnX
XnXn
Y
XY
XnY
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