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- 10-27. A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then 4.373 g of solution were titrated with 14.22 mL of 0.106 3 M HCl to reach a bromocresol green end point. (a) What fraction of the 10.231-g sample of window cleaner is contained in the 4.373 g that were analyzed? (b) How many grams of NH3 (FM 17.031) were in the 4.373-g sample? (c) Find the weight percent of NH3 in the cleaner.d. 1.10 g of K3PO4 in 430.0 mL of solution Mx+ =| M %3D Mpo, MThe Ksp value of CaSO4 is 2.4 x 10-5. If a professor made 1500 mL of a CaSO4 solution, then how many grams of Ca²+ ion would be present in the solution?
- A reagent bottle contains 250 cm3 of 0,4 mol.dm–3 oxalic acid(C2O4H2) solution. Calculate the mass of pure oxalic acid thatmust be dissolved in this solution so that its new concentration is 0,6 mol.dm–3. Assume that the volume of the solution remainsconstantA 0.1475-M solution of Ba(OH)2 was used to titrate the acetic acid (60.05 g/mol) in a dilute aqueous solution. The following results were obtained. (See attached image)(a) Calculate the mean w/v percentage of acetic acid in the sample.(b) Calculate the standard deviation for the results.(c) Calculate the 90% confidence interval for the mean.(d) (d) At the 90% confidence level, could any of the results be discarded?What’s the ratio M/A for the 7.5 ml Dilution?
- 1. A sample of an infusion was diluted 10 ml to 250 ml and then 10 ml to 200 ml. It was then analysed and was found to contain sodium at 0.789 mg/100 ml. Calculate the concentration of sodium in the original sample in %w/v. The sample was composed of a mixture of sodium lactate and sodium carbonate in equimolar amounts. Calculate the amount of sodium lactate and sodium carbonate in mg/10 ml of the sample (Na = 23, lactate = 89, carbonate = 60) 2. 0.641 g of a semi-synthetic alkaloid was dissolved in 25 ml of 1% w/v acetic acid and was analysed directly by HPLC. The solution was found to contain 1.42 mg/100 ml of an impurity. What is the level of impurity in % w/w and ppm? 3. Calculate the pH of a buffer system made by dissolving 1.2 g of acetic acid and 0.82 g of sodium acetate in 500 ml of distilled water (pKa of acetic acid = 4.7) 4. Convert the following concentrations into the required expression. Concentration given Expression required 0.5% NaCl molarity 1 mM of KBr…Table of chemicals and reagents with their physicochemical properties (name, molecular formula, molecular weight, pKa, melting point, boiling point, etc.) Write a short outline or a flow diagram of the procedure List and safety issues Read and understand the MSDS information for each chemical used in this practical Experimental procedure Please do not scratch the clear sides of the UV cuvettes as this will invalidate your results. Part 1: Preparation of a calibration curve A calibration curve should be constructed using at least five concentrations of the pure paracetamol standard supplied in the range 3-15 ug/mL as follows: Weigh about 150 mg of paracetamol accurately and transfer to a 200 mL volumetric flask. Add 50 mL of o.1 M NaOH and dilute to about 100 mL with deionised water (DI). Shake and make up to volume with DI water. Dilute 10 mL of the resulting solution to 100 mL (volumetric flask) with DI water (= stock solution). Prepare standard solutions containing 3, 6, 9, 12 and 15…Calculate the concentration of Ca**, Cl in mM/L and meq/L; and hardness in mg/L as CaCO3 produced by the addition of 200 mg/L CaCl, to pure water. 4:39 PM
- The Ksp for LaF3 is 2 x 10-19. What is the solubility of LaF3 inwater in moles per liter?The melting temperature of pure acetylsalicylic acid is 135 degrees Celsius. Based on the results of the melting temperature test, what is the percent purity of your sample of aspirin? Part I Synthesis of Aspirin Mass of salicylic acid used (g) 2.029g Volume of acetic anhydride used (mL) 5ml Mass of acetic anhydride used (vol. × 1.08 g/mL) 5.4g Mass of aspirin synthesized (g) 3.256g Part II Melting Temperature Data Melting temperature (°C) 133°C Part III Salicylic Acid Standard Stock Solution Initial mass of salicylic acid (g) 0.210g Moles of salicylic acid (mol) 0.0147 mol Initial molarity of salicylic acid (M) 0.724 M Part III Beer’s Law Data for Salicylic Acid Standard Solutions Trial Concentration (M) Absorbance 1 10 0.301 2 7.5 0.219 3 5.0 0.163 4 2.5 0.074 Best-fit line equation for the salicylic acid standards Test of the Purity of the…chools.schoology.com/common-assessment-delivery/start/4573067641?action%3Donresume&submissionld%3547892539 150 140 130 120 110 100 NANO 90 80 70 60 NH C Ka Náci 50 40 30 20 KCIÓ, 10 Cez(so 10 20 30 40 50 60 70 80 90 100 Temperature (C) The compound with the least solubility at 50 °C is OKI O NANO3 O KNO3 O NH3 O NH&CI O KCI O NaCI O KCIO3 O Cex(SOa)a DELL & Grams of solute