What is the subnet address if the one of the address in the subnet is 200.45.34.56 and the mask is 255.255.240.0
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A: Solution: 192.168.3.55/24 Here /24 means number of network bits is 24 and number of host bits is…
Q: A supernet has first address of 205.16.32.0 and a supernet mask of 255.255.248.0. Prove that the…
A: Default Mask: 255 255 255 0 11111111 11111111 11111111 00000000
Q: Höst åddress in a subnet. Suppose you - subnet mask is 255.255.255.240 what would ba our dafe
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Q: 1- Compute the subnet mask, subnet address, broadcast address and the IP host ranges of…
A: To compute the subnet mask, subnet address, broadcast address and the IP host ranges
Q: Give the example of two (sub) network masks for which the address 171.28.289.127 is the broadcast…
A: Give the example of two (sub) network masks for which the address 171.28.289.127 is the broadcast…
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Q: q11- 127.0.0.0 – 127.255.255.255 Address range is used for ? a. Limited broadcast address…
A: The solution for the above given question is given below:
Q: Given the following subnet mask, what is its representation in CIDR notation? 255.255.254.0 What is…
A: Given: 255.255.254.0 To Find: CIDR notation: 255.255.255.254/31
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Q: 192.165.1.9 11000000.10100101.00000001.00000111 255.255.255.224 11111111.11111111.11111111.11100000…
A: Step 1:- Given:- 192.165.1.9 The binary form of 192.165.1.9 is 11000000.10100101.00000001.00000111…
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A: * As far bartleby guidelines, I answer first-sub question (a) in the multiple sub questions in that…
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A: Introduction: Given: We have a single network having IP Address 198.53.202.0We want to do subnetting…
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Q: Consider the four networks 200.96.86.0, 200.96.87.0, 200.96.88.0 and 200.96.89.0. What are the…
A: Explanation: An_IP_address_is_an_identifier_or_label_used_to_identify_a_machine_on_…
Q: 223.23.223.109 10.10.250.1 126.123.23.1 223.69.230.250 Custom Subnet mask Number of needed subnets…
A: 128.77.0.0 Number of usable subnet = 60 Number of subnet bits = ceil(log 60) = 6 bits. Address…
Q: Given a CIDR address 138.112.25.60/x and the mask 255.255.255.240, what is the value of x? between…
A: The question is on given a CIDR address 138.112.25.60/x and the mask 255.255.255.240, what is the…
Q: Network address: 10.0.0.0 Subnet mask: 255.255.248 What are the first host, last host and broadcast…
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Q: 1) Write the correct default subnet mask for each of the following addresses: i. 191.249.234.191…
A: Solution :- i. 191.249.234.191 it is of class B network so 16 bits are held for network id implies…
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A: Definition: Supernet: It is also called as the super network. In this we will have a lots of…
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A: Host bits are calculated for the IP addresses in the below step
Q: 10.129.255.100 255.248.0.0 How many addresses in this subnet?
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Q: What is the host address of 200.32.71.14/20?
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Q: In a classful addressing, first four bits in Class A IP address is a. 1010 b. 1100 c. 1011 d. 1110
A: Here in this question we have given class A classfull addressing.and asked about the four bit which…
Q: B) IP address 200.172.138.62 11001000.10101100.10001010.111110 Subnet 255.255.255.240 11111111.…
A:
Q: What would be the valid subnet address of the host 180.50.33.33/18? O 180.50.64.0/18 180.50.128.0/18…
A: Valid subnet address of the host 180.50.33.33/18 is:
Q: Compute the subnet mask, subnet address, broadcast address and the IP host ranges of 192.168.3.55/24…
A: Given 192.168.3.55/24 In this /24 means number of network bits is 24 and number of host bits is 8.…
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Q: What is the host address of 126.42.13.99 with a 255.255.0.0 subnet mask?
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A: A) The subnet mask contains 27 1's and 5 0's. This means total number of host bits is 5. For network…
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Q: How many bits borrowed from this subnet mask? 6 bits 255.255.255.252
A: Here have to determine about bit borrowed from subnet mask.
Q: 192.165.1.0 11000000.10100101.00000001.00000000 255.255.255.224 11111111. 11111111.11111111.11100000
A: Here, The subnet mask contains 27 1's and 5 0's. This means the number of host bits is 5. A) For…
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A: Subnet Mask : - 255.255.240.0 It is a class B network.For a class B network, the upper 16 bits form…
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Q: Based on the subnet mask, 255.255.255.0, how many computers can be addressed on the subnet on which…
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Q: 1- Compute the subnet mask, subnet address, broadcast address and the IP host ranges of…
A: 192.168.3.55/24 Here /24 means number of network bits is 24 and number of host bits is 8. Therefore…
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What is the subnet address if the one of the address in the subnet is 200.45.34.56 and the mask is 255.255.240.0?
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- Given a CIDR address 138.112.25.60/x and the mask 255.255.255.240, what is the value of x? between 138.112.25.47/x and 138.112.25.49/x, which one is in the same subnetwork as 138.112.25.60 is and which one is not?A TCP connection is using a window size of 8,000 bytes and the previousacknowledgment number was 10,001. It receives a segment with acknowledgment number 12,001 and window size advertisement of 7,000 bytes. Draw a diagram to show the situation of the window before and after.Please solve it correctly and please provide explanation of your answers. Please answer parts g, h and i. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. g) The second segment from webserver was corrupted. So the PC…
- In Point to Point Protocol, the address value in the frame is: A. Always 255.255.255.256 B. None is true. C. Always 255.255.255.255 D. Always 00 00 00 00 00 00 E. Always FF FF EF EF EF F. ww wm v w wwFor NAT Network Address Translation Scenario: Jenny Bello is a small business owner selling and making customized computer peripherals. She has been finding it difficult to track her sales and inventories, however recently after an expert's advice, she adopted a Point of Sale (PoS) server. So, she can now track her sales and inventories at the store. However, she ran into another issue, the server can only be accessed within the store, because it has been assigned a private IPv4 address, it is not publicly accessible via the Internet. a) Why is not having the PoS server accessible over the Internet a problem for the business? b) What caused this problem? c) Propose a solution for the problem and explain how the solution works.Suppose Alice and Bob are going to communicate using AES in CBC mode. Unfortunately Alice's message length (in bytes) is not a multiple of 16. Suppose the last block of her message is just a single zero byte. How can she pad out the last block so that she can use CBC mode? Since this needs to be a reversible operation, how does Bob recognize the padding and remove it?
- The MAC address of my PC is 18-6B-2C-99-DD-7A (in hexadecimal format). Write this out as a 48-bit binary value. Your answer should consist of 48 values, each of which is 0 or 1.The minimum number of columns in a datagram network is two; the minimumnumber of columns in a virtual-circuit network is four. Can you explain thereason? Is the difference related to the type of addresses carried in the packetsof each network?The minimum number of columns in a datagram network is two; the minimum number of columns in a virtual-circuit network is four. Can you explain the reason? Is the difference related to the type of addresses carried in the packets of each network?
- UDP and TCP Use 1s complement for their checksums. Suppose you have the following three bytes: 10101110, 10101001, 00101011 what is the 1s complement of the sum of these three bytes?UDP and TCP use 1’s complement for their checksums to detect errors. Suppose you have the following 8-bit bytes: 11011001, 01010010, 11001010, 10100100 and 01011001. A. What is the 1’s complement of the sum of these 8-bit bytes? Show all the details of your work. B. Why do UDP and TCP take the 1’s complement of the sum as their checksum? That is, what do UDP and TCP not simply use the sum of these bytes as checksum? C. With the 1’s complement scheme, how does the receiver detect errors? D. With this checksum scheme, is it possible that any l-bit error will go undetected? How about a two-bit error? Explain your answer.The registers contain the following values. CS = 020AH, SS = 0801H, SI = 0100H, IP 1BCDH In this case, what would be the address of the next instrution? 03C6DH 03C70H 03D5DH None of the above 03D5EH