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- Nitration of Benzene with H,SO, will produce? O 1-Nitrobenzene O Dioxy ntrogen benzene O Al O NitrobenzeneWhich set of reagents enable the transformation depicted below? OEt ??? O Palladium on carbon (Pd/C) + hydrogen gas (H₂) O Lindlar's catalyst NaBH4 in Methanol O 1.) LiAlH4 followed by: 2.) H₂O O 1.) Dibal-H followed by: 2.) H₂O HO OEtGive the major products for each of the following reactions ОН PCC CH₂Cl2 __ОН CrO3, H₂SO4 1. LiAlH4, THF 2. Н3О+ 0 ОН ОН SOCl2 pyridine MsCl pyridine
- If anhydrides react like acid chlorides with the nucleophiles, draw the products formed when each of the following nucleophiles reacts with benzoic anhydride [(C6H5CO)2O]: (a) CH3MgBr (2 equiv), then H2O; (b) LiAlH4, then H2O; (c) LiAlH[OC(CH3)3]3, then H2O.Which of the following reaction condition will carry out the following transformation? он OCH3 осн а-1-LIAH4 2- H3O* d- 1- NaH 2- H30* b- 1- CH3MgBr с- 1-NaBHз 2- H30* 2- H3O*12210: WS12 Provide the major organic product of the following reaction. NBS, Heat ROOR
- In a standard nitration reaction with HNO3 and H₂SO4, the following compound forms a single nitration product. What is its structure? Me HN HNO₂ H₂SOAWhich of the following is the best method to carry out the following transformation? OH (a) H₂SO4, H₂O (b) 1. BH3 2. H₂O2, OH (c) 1. Hg(OAc)₂2 H₂O 2. NaBH. (d) 1. HBr 2. H₂OIdentify the reagents, in correct order, expected to accomplish the following transformation. O H2SO4. HBr/ROOR; HOET O NBS/A; NaOEt O N2OET; Br2 O NBS/A; N2OH: HOEE O NazCr207/H2SO/H2O; NaOH; EtBr
- Qunhstion 12 Two products below results from the ozonolysis reaction of an unknown unsaturated hydrocarbon compound. Give the structure of the unsaturated hydrocarbon. andWhat is the final product of the multi-step synthesis sequence of reactions shown? NANH, NH; LINH; Product A Benzyl bromide (CH),Culi excess Product C Final Product Product B в Compound C Compound A Compound B A 50:50 mixture of Compounds A and B None of the above are the correct Final ProductBr Brz CH3 CH3 H3C CH2CI2 H3C Br Electrophilic addition of bromine, Br2; to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl). In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br: :Br: .CH3 H3C H3C CH3 Br: