To better understand how the lacR works, let's start let's approximate the volume of a bacterial cell by treating it as a cylinder with radius that is 0.5 um and length that is 2 um. What is the volume of the cylinder in liters, L)? Next, let's calculate the concentrations of the lacR (ligand) and the operator site (Op) (primary receptor) in this volume. There are 10 lacR molecules in the cell and 1 operator site. Using this information calculate [lacR] and [Op] in molar units in one cell? (see eq. 13.17 and 13.18).

Biochemistry
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Chapter1: Biochemistry: An Evolving Science
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) To better understand how the lacR works, let's start let's approximate the volume of
a bacterial cell by treating it as a cylinder with radius that is 0.5 um and length that is
2 um. What is the volume of the cylinder in liters, L)?
Next, let's calculate the concentrations of the lacR (ligand) and the operator site
(Op) (primary receptor) in this volume. There are 10 lacR molecules in the cell and 1
operator site. Using this information calculate [lacR] and [Op] in molar units in one
cell? (see eq. 13.17 and 13.18).
Transcribed Image Text:) To better understand how the lacR works, let's start let's approximate the volume of a bacterial cell by treating it as a cylinder with radius that is 0.5 um and length that is 2 um. What is the volume of the cylinder in liters, L)? Next, let's calculate the concentrations of the lacR (ligand) and the operator site (Op) (primary receptor) in this volume. There are 10 lacR molecules in the cell and 1 operator site. Using this information calculate [lacR] and [Op] in molar units in one cell? (see eq. 13.17 and 13.18).
[lacR] total
10 molecules
·X·
6x102³ molecules mol-¹10-¹5 L
2×108 M
1
(13.17)
The concentration of the single operator site in the cell, [Op]total, is given by:
1 site
1
[Op]total =
-X
-1
6x1023 sites mol-¹ 10-¹5 L
≈2×10⁹ M
(13.18)
Transcribed Image Text:[lacR] total 10 molecules ·X· 6x102³ molecules mol-¹10-¹5 L 2×108 M 1 (13.17) The concentration of the single operator site in the cell, [Op]total, is given by: 1 site 1 [Op]total = -X -1 6x1023 sites mol-¹ 10-¹5 L ≈2×10⁹ M (13.18)
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