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To a solution containing 1.50 x 105 M in lodide (I-) and 4.20 M in Chloride (Cl-) ions, fractional precipitation is tried by adding Ag(NO3)2(aq) as the precipitating agent. Based on this data, we can conclude that Agl will precipitate first before AgCl. Given are the Ksp values: Agl: 8.50 x 1017 ; AgCl: 1.80 x 1010 Select one: O True O False

To a solution containing 1.50 x 105 M in lodide (I-) and 4.20 M in Chloride (Cl-) ions, fractional precipitation is tried by adding Ag(NO3)2(aq) as the precipitating agent. Based on this data, we can conclude that Agl will precipitate first before AgCl. Given are the Ksp values: Agl: 8.50 x 1017 ; AgCl: 1.80 x 1010 Select one: O True O False

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter15: Solubility And Complex Lon Equilibria
Section: Chapter Questions
Problem 106CP: A mixture contains 1.0 103 M Cu2+ and 1.0 103 M Mn2+ and is saturated with 0.10 M H2S. Determine a...
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To a solution containing 1.50 x 105 M in lodide (1-) and 4.20 M in Chloride (CI-) ions, fractional precipitation is tried by adding Ag(NO:)2(aq) as the precipitating agent. Based on this data, we can conclude that Agl will precipitate first before AgCl. Given are the Ksp values: Agl: 8.50 x 10-17 ; AgCl: 1.80 x 1010 Select one: O True O False
Transcribed Image Text:To a solution containing 1.50 x 105 M in lodide (1-) and 4.20 M in Chloride (CI-) ions, fractional precipitation is tried by adding Ag(NO:)2(aq) as the precipitating agent. Based on this data, we can conclude that Agl will precipitate first before AgCl. Given are the Ksp values: Agl: 8.50 x 10-17 ; AgCl: 1.80 x 1010 Select one: O True O False
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